# Print Diamond Star Pattern

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*****

*******

*****

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## PREREQUISITE:

Basic knowledge of C language and use of loops.

## ALGORITHM:

1. Take the number of rows as input from the user and store it in any variable.(‘r‘ in this case).
2. Run a loop ‘r’ number of times to iterate through each of the rows. From i=0 to i<r. The loop should be structured as for( i=0 ; i<r : i++).
3. Use an if condition to to print the top half of the diamond. if (i<=r/2). Then run a loop from k=r/2 to k>i. The loop should be structured as for(k=r/2 ; k>i ; k–). Inside this loop print space.
4. After this inside the if block run another loop from j=0 to j<=i*2. The loop should be structured as for(j=0 ; j<=i*2 ; j++)
5. Inside this loop print star.
6. Else run a different loop from k=r/2 to k<i, The loop should be structured as for( k=r/2;k<i ;k++).  Inside this loop print space
7. Run another loop inside the else block from j=i to j<((r-i)*2)-1. The loop should be structured as for( j=0 ; j<((r-i)*2)-1 ; j++).
8. Inside this loop print star.
9. Inside the main loop print a newline to move to the next line after each row is printed.

## CODE IN C:

```#include<stdio.h>
int main()
{
int i,j,k,r;      //declaring integer variables i,j,k for loops and r for number of rows
printf("Enter the number of rows :\n"); //Asking user for input
scanf("%d",&r);                         //saving number of rows in variable r
for(i=0;i<r;i++)                       //outer loop for number of rows
{
if(i<=r/2)                       //if condition to print the top half of diamond
{
for(k=r/2;k>i;k--)          //nested loop for number of spaces
{
printf(" ");           //printing spaces
}
for(j=0;j<=i*2;j++)         //nested loop for printing stars
{
printf("*");          //printing stars
}
}
else                              //else condition to print the bottom half of the diamond
{
for(k=r/2;k<i;k++)          //nested loop to print spaces
{
printf(" ");         //printing spaces
}
for(j=0;j<((r-i)*2)-1;j++)  //loop to print star
{
printf("*");        //printing stars
}
}
printf("\n");                   //printing newline
}
}```

## DISPLAYING OUTPUT:

### 2 comments on “Print Diamond Star Pattern”

• Arthi

#python
n = int(input())
c1 = 1
c = n//2+1
for i in range(c):
print(‘ ‘*(c-i-1)+’*’*(2*i+1))
for j in range(n-2,0,-2):
print(‘ ‘*c1+’*’*j)
c1 +=1

• Tejasri

python
n=int(input())
a=n+n-1
for i in range(a):
if i<n:
print(" "*(n-1-i)+"*"*(i+i+1))
else:
print(" "*(i+1-n)+"*"*(2*(a-i)-1))