Increment Numbered Square Printing
PRINTING PATTERN:
1111
2222
3333
4444
PREREQUISITE:
Basic knowledge of C language and loops.
ALGORITHM:
- Take number of rows/columns as input from the user and save it in any variable (‘r’in this case).
- Run a loop ‘r’ number of times to iterate through the rows. From i=0 to i<r. The loop should be structured as for( i=0 ; i<r ; i++).
- Run a nested loop inside the previous loop to iterate through the columns. From j=0 to j<r. The loop should be structured as for(j=0 ; j<r ; j++).
- Inside the nested loop print ‘i’ to print the incremented value in each column of a row.
- Inside the main loop print a newline to move to the next line after a row.
CODE IN C:
#include<stdio.h> int main() { int i,j,r; //declaring integer variables i,j for loops , r for number of rows printf("Enter the number of rows/columns :\n"); //asking user for the number of rows; scanf("%d",&r); //taking number of rows and saving in variable r for(i=1;i<=r;i++) //loop for number of rows { for(j=0;j<r;j++) //loop to print digit in every column of a row { printf("%d",i); //printing digit } printf("\n"); //printing newline } }
TAKING INPUT:
DISPLAYING OUTPUT:
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n=int(input())
for i in range(1,n+1):
for j in range(n+1):
print(i,end=””)
print(“\n”)