C Program to Check if a Given Number is Armstrong Number or Not

2 comments on “C Program to Check if a Given Number is Armstrong Number or Not”

• 
  

  Sushil

  #include
  int F(int temp,int t)
  {
  int i,x=1;
  for(i=1;i<=t;i++)
  {
  x=x*temp;
  }
  return x;
  }
  int main()
  {
  int n;
  printf("Enter a number :\n");
  scanf("%d",&n);
  int t=0,sum=0,temp,p=n,q=n;
  while(n!=0)
  {
  t++;
  n=n/10;
  }
  while(p!=0)
  {
  temp=p%10;
  sum=sum+F(temp,t);
  p=p/10;
  }
  if(sum==q)
  {
  printf("\nArmstrong number.");
  }
  else
  {
  printf("\nNot armstrong number.");
  }
  }

  0

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• 
  

  Anjali

  import java.util.*;
  import java.io.*;
  class arm
  {
  public static void main(String[] args) {
  int sum=0;
  Scanner sc=new Scanner(System.in);
  String a = sc.next();
  char[] ch = a.toCharArray();
  for(int i=0;i<ch.length;i++){
  sum+=Math.pow(Character.getNumericValue(ch[i]),3);
  }

  if(sum == Integer.parseInt(a)){
  System.out.println("Armstrong Number");
  }
  else{
  System.out.println("Not an Armstrong Number");
  }
  }
  }

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