Accenture Coding Question 14

August 31, 2021

Coding Question 14

Instructions: You are required to write the code. You can click on compile & run anytime to check the compilation/ execution status of the program. The submitted code should be logically/syntactically correct and pass all the test cases.

Ques: The program is supposed to calculate the distance between three points.

For,

x1 = 1, y1 = 1
x2 = 2 , y2 = 4
x3 = 3, y3 = 6

Distance is calculated as : sqrt(x₂-x₁)² + (y₂-y₁)²

Python

C++

Java

#include <stdio.h>
#include <math.h>

int isDistance(float *pt1, float *pt2, float *pt3)
{
float a, b, c;
a = sqrt(((pt2[0]-pt1[0])*(pt2[0]-pt1[0]))+((pt2[1]-pt1[1])*(pt2[1]-pt1[1])));
printf(“%f”,a);
b = sqrt(((pt3[0]-pt2[0])*(pt3[0]-pt2[0]))+((pt3[1]-pt2[1])*(pt3[1]-pt2[1])));
printf(“%f”,b);
c = sqrt(((pt3[0]-pt1[0])*(pt3[0]-pt1[0]))+((pt3[1]-pt1[1])*(pt3[1]-pt1[1])));
printf(“%f”,c);
}

int main()
{ 
int t;
float p1[2], p2[2], p3[2];
printf("enter x1 and y1 : ");
scanf("%f%f",&p1[0],&p1[1]);
printf("enter x2 and y2 : ");
scanf("%f%f",&p2[0],&p2[1]);
printf("enter x3 and y3 : ");
scanf("%f%f",&p3[0],&p3[1]);
t = isDistance(&p1, &p2, &p3);
printf("%d",t);
return 0;
}

Python

import math

x1, y1 = 1, 1
x2, y2 = 2, 4
x3, y3 = 3, 6

first_diff = math.sqrt(math.pow(x2-x1, 2) + math.pow(y2-y1, 2))
second_diff = math.sqrt(math.pow(x3-x2, 2) + math.pow(y3-y2, 2))
third_diff = math.sqrt(math.pow(x3-x1, 2) + math.pow(y3-y1, 2))

print(round(first_diff,2), round(second_diff,2), round(third_diff,2))

C++

#include <bits/stdc++.h>
using namespace std;

int isDistance(float *pt1, float *pt2, float *pt3)
{
    float a, b, c; 
    
    a = sqrt(((pt2[0]-pt1[0])*(pt2[0]-pt1[0]))+((pt2[1]-pt1[1])*(pt2[1]-pt1[1])));
    cout<<a;
    
    b = sqrt(((pt3[0]-pt2[0])*(pt3[0]-pt2[0]))+((pt3[1]-pt2[1])*(pt3[1]-pt2[1])));
    cout<<b;
    
    c = sqrt(((pt3[0]-pt1[0])*(pt3[0]-pt1[0]))+((pt3[1]-pt1[1])*(pt3[1]-pt1[1])));
    cout<<c;
}

int main()
{ 
    float p1[2], p2[2], p3[2];
    
    cout<<"Enter x1 and y1 : ");
    cin>>p1[0]>>p1[1];
    
    cout<<"Enter x2 and y2 : ");
    cin>>p2[0]>>p2[1];
    
    cout<<"Enter x3 and y3 : ");
    cin>>p3[0]>>p3[1];
 
    isDistance(&p1, &p2, &p3);
    
    return 0;
}

Java

import java.util.*;
class Solution 
{
 
    public static void main (String[]args) 
    {
        Scanner sc = new Scanner (System.in);
        int x1 = 1, y1 = 1;
        int x2 = 2, y2 = 2;
        int x3 = 3, y3 = 3;
        int firstDiff =(int) Math.sqrt (Math.pow (x2 - x1, 2) + Math.pow (y2 - y1, 2));
        int secondDiff =(int) Math.sqrt (Math.pow (x3 - x2, 2) + Math.pow (y3 - y2, 2));
        int thirdDiff =(int) Math.sqrt (Math.pow (x3 - x1, 2) + Math.pow (y3 - y1, 2));

        System.out.println (firstDiff + " " + secondDiff + " " + thirdDiff);
    } 
}