Print Number Star Square Pattern Type 4

June 23, 2019

PRINT PATTERN  1*2*3*4  9*10*11*12

For any input number N Print the following code – For below code N=4

1*2*3*4
9*10*11*12
13*14*15*16
5*6*7*8

PREREQUISITE:

Basic knowledge in Java programming, usage of loops.

ALGORITHM:

  1. Take input from user i.e number of lines required (N value).
  2. Take two loops one for each line (say ‘i’) and other for each digit in a particular line (say ‘j’). i starts from 1 and j starts from 1.
  3. Take a result variable (say ‘m’) and initialize it with 1.
  4. Here ‘i’ loop is used to access each line from 1 to n-1 and ‘j’ loop is used to print values in each line. First j loop executes when i not equal to 1 and other j loop runs in remaining cases.
  5. Print ‘m’ value along with * and post increment  until the j loop reaches a value less than n.
  6. Print the final value ‘m’ of each line.
  7. Repeat the ‘i’ loop until it reaches n-1.

CODE IN JAVA:

[code language=”java”]
import java.lang.*;
import java.io.*;
class Pattern
{
public static void main(String[] args)throws IOException
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int n,i,j,m=1;
System.out.print("Enter N value:");
n=Integer.parseInt(br.readLine());
for(i=1; i<=n-1; i++)
{
if(i!=2)
{
for(j=1; j<n; j++){
System.out.print((m++)+"*");
}
System.out.print(m++);
System.out.println();
}
else {
m = m+n;
for(j=1; j<n; j++){
System.out.print((m++)+"*");
}
System.out.print(m++);
System.out.println();
}
}
for(i=n+1 ;i<(n+n);i++){
System.out.print(i+"*");
}
System.out.print(i);
System.out.println();
}
}
[/code]

TAKING INPUT:

DISPLAYING OUTPUT:

 

1 comments on “Print Number Star Square Pattern Type 4”


  • kamtamamulya5

    public class alternate_number2
    {
    public void meth()
    {
    int a=1,t=0,n=6,prev=1;

    for(int i = 0; i <n;i++)
    {
    if(i != 0 && i != n-1)
    {
    t = a+n;

    for(int j = 0; j <n;j++)
    {
    System.out.print((t++)+" ");
    }
    a = t-prev+1;

    System.out.println();
    }
    else
    {
    a = prev;

    for(int j=0;j <n;j++)
    {
    System.out.print((a++)+" ");
    }
    prev = a;
    System.out.println();
    }
    }
    }
    public static void main(String[] args)
    {
    new alternate_number2().meth();
    }
    }