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June 23, 2019
Question 1
In a school, 10% of the number of girls is equal to 1/20 of a number of boys. The ratio between the 'number of boys to the number of girls is
1:2
2:1
1:4
4:1
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If boys = x and girls = y, then Y * (10/100) = x/20 y/10 = x/20 x/y=20/10 =2/1
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Question 2
The ratio of 25^2.5 : 5^3 is same as
1:5
5:1
1:25
25:1
252.5 : 53 = (52)2.5 : 53 = 55 : 53 = 52 : 1 = 25 : 1
Question 3
Equal quantities of three mixtures of milk and water are mixed in the ratio 1:2, 2:3 and 3:4. The ratio of water and milk in the mixture is:
193:122
61:97
137:178
122:193
(1:2),(2:3),(3:4) (1+2),(2+3),(3+4) 3,5,7 equal quantities of mixture i.e. lcm of 3,5,7=105 105/3=35 , 105/5=21 , 105/7=15 (35*1,35*2),(21*2,21*3),(15*3,15*4) (35,70),(42,63),(45,60) so overall mixture ratio is 35+42+45:70+63+60 122:193
Question 4
Flights A and B are scheduled from an airport within the next one hour. All the booked passengers of the two flights are waiting in the boarding hall after check-in. The hall has a seating capacity of 200 out of which 10% remained vacant. 40% of the waiting passengers are ladies. When boarding announcements came, passengers of flights A left the hall and boarded the flight. Seating capacity of each flight is two-thirds of the passengers who waited in the waiting hall for both the flights put together. Half the passengers who boarded flight A are women. After boarding for flight A, 60% of the waiting hall seats became empty. For every twenty of those who are still waiting in the hall for flight B, there is one air hostess in flight A. Then, what is the ratio of empty seats in flight B to the number of air hostesses in flight A?
10:1
20:1
1:1
Hall capacity 200 10%vacant -- so 180 passengers waiting 40% i.e 72 are women seating capacity of each flight = 2/3 *180 =120 after boarding flight a, 60% i.e 60/100 *200 =120 seats became vacant so 80 people are still waiting i.e. 100 people boarded the flight . 80/20 =4 air hostesses. 120-80 = 40 empty seats in flight b. 40:4 = 10:1
Question 5
Instead of walking along two adjacent sides of a rectangular field, one can take a shortcut along the diagonal of the field and save a distance equal to half of the longer side. Find the ratio of the shorter side to the longer side.
2:5
4:3
3:4
We know that for any diagonal in this rectangle described that a^2 + b^2 = c^2. Now, by walking the c^2 path, he saved half the distance of b we will say, and call b the longer side, so we know: c = a + b - b/2, or c = a + b/2 Now, putting this in to the first equation: a^2 + b^2 = (a + b/2)^2 Expand: a^2 + b^2 = a^2 + ab + b^2/4 Cancel: (3/4)b^2 = ab Divide by b: (3/4)b = a So, the ratio is 3:4.
Question 6
The payment per hour for a daily-wages employee is increased by 33.33 and the working time is reduced by 33.33%. What is the percentage change in the employee's income?
11.11% decrease
21.11% increase
11.11% increase
21.11% decrease
If earlier he is getting Rs. 1 per hr and working for 1 hr, income = Rs. 1 Now he is getting Rs 1.3333 per hr and working for 0.66667 hrs Then income for 0.66667 hrs = Rs. 0.8889. If payment per hr is increased by 33.33 % and working hours decreased by 33.33%, then 11.11 % decrease in income.
Question 7
The ratio of present ages of X and Y is 4:5. Which of the following can't be the ratio of ages of X and Y, 20 years ago?
2:4
9:10
2:3
3:5
The ratio of X and Y ages at present is 4:5. Then, the ratio 20 years ago will not be more than the ratio at present. So, from the options 9:10 is not satisfying => its ratio is 0.9 which is greater than present ratio of 0.8.
Question 8
Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
4:5
5:4
Let the third number be x. Then, first number = 120% of x =120x/100 = 6x/5 Second number =150% of x = 150x/100 = 3x/2 Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5
Question 9
A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?
Rs. 500
Rs. 1500
Rs. 2000
None of these
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively. Then, 4x - 3x = 1000 x = 1000. B's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
Question 10
Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
2 : 3 : 4
6 : 7 : 8
6 : 8 : 9
Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively. Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x). 7x, 21x/2 and 14x. The required ratio = 7x :21/2x: 14x 14x : 21x : 28x 2 : 3 : 4.
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