Hiremee Simple and Compound Interest Questions with Answers

S.I. = Rs. (15500 ⎯ 12500) = Rs.3000

Rate = [ 100 × 3000 / 12500 × 4 ]% = 6%

Let the sum invested in scheme A be Rs. x and that in scheme B be Rs. (13900 ⎯ x)
Then, [ x × 14 × 2 / 100] ÷ [{(13,900 - x) × 11 × 2 } / 100] = 3508

28x ⎯ 22x = 350800 ⎯ (13900 × 22)

6x = 45000

x = 7500

So, sum invested in Scheme B = Rs. (13900 ⎯ 7500) = Rs.6400

(b) 20years

Let rate = R% and time = R years

Then, [1200 × R × R / 100] = 432

12 r2 = 432

R2 = 36
R = 6

At 10% CI in 2 years=21 %
At 20% Ci in 2 years =44%
and 5350 is 107/4% of 20000, by using allegation
A B
21 44
107/4
3 1
A=3/4*20000= Rs 15000

Sum=353; Amount=512
as many year, put that many root i.e
cuberoot(343): cuberoot(512)
7:8
rate=(8-7)/7 *100 =14 (2/7)%

Sum= A
Interest= B
A——–A———A
———-B———B
———————B
———————C
CI for 3 years=3A+3B+C
SI for 3 years =3A
Diff= 3B+cCI for 2 years=2A+B
SI for 2 years=2A
diff=B
ratio=(3B+C)/B=31/10
B=10; C=1
Rate=C/B=1/10=10%

Formula= x/(1+R/100)^T
x/ (1+20/100)^1 + x/(1+20/100)^2 = 6600
solve and get x=4320