Java program to remove brackets from an algebraic expression

October 14, 2022

Remove brackets from an algebraic expression

In this program, we’re going to remove brackets from an algebraic expression. Take a String input from the user and store it in the variable called “s”. After that use replaceAll() method which was present in string class the work of replaceAll() method is to replace some old thing with some new thing so here we’re using a regular expression to replace brackets with white spaces from an algebraic expression like s.replaceAll(“[(){}]”,””) and after that simply print new expression which doesn’t have any brackets.

Java program to remove brackets from an algebraic expression

Algorithm

  • First take String input from user and Store it in the variable called as “s”.
  • After that use replaceAll() method .
  • Use regular expression to replace brackets present in algebraic expression with whitespaces.
  • Atlast simply print that expression after removing brackets.

Code in Java

Run 
import java.util.Scanner;

public class Main {

public static void main(String[] args) {
     
     String s = "(a+b)=c";
     String result = s.replaceAll("[(){}]","");
     System.out.println("Expression without brackets : "+result);
  }
}

Output

Expression without brackets : a+b=c
 
 

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3 comments on “Java program to remove brackets from an algebraic expression”


  • Surya

    #python code

    string1=input()
    string2=str()
    for i in string1:
    if (i==”)” or i==”(“):
    pass
    else:
    string2=string2+i
    print(string2)


  • NITIN

    In Python:-
    n = input()
    a = ”
    for i in n:
    if i == ‘(‘ or i == ‘)’ or i== ‘[‘ or i==’]’ or i== ‘{‘ or i== ‘}’ :
    continue
    else:a = a+i
    print(a)


  • S

    s1=input()
    s2=str()
    for i in s1:
    if i==”(“or i==”)”:
    pass
    else:
    s2=s2+i
    print(s2)
    in python