Find the Nth Term of a Fibonacci Series in Python

April 20, 2022

Nth Term of a Fibonacci Series

On this page we will learn how to Find the Nth Term of a Fibonacci Series  in Python.

Using two Different Methods

  1. Using Loop
  2. Using Recursion
  • Input : 6
  • Output : 5
  • Explanation : Fibonacci series is the sum of the previous two terms, so if we enter 6 as the input in the program, so we should get 5 as the output.
Factorial of a Number in Python

Method 1 : Using Loop

Algorithm

  • Start
  • If n is less then 2 return n
  • Initialize a array with value 0 & 1 respectively named fs
  • Use  a for loop to iterate between range 1 to n using variable i
  • For each iteration append the sum of current element and previous element to fs
  • Return the Nth element of fs
Python Program to find Nth Term of a Fibonacci Series

Python Code

Run 
def Fibonacci(n):
    if n < 2:
        return n
    fs = [0, 1]
    for i in range(1, n):
        fs.append(fs[i] + fs[i - 1])
    return fs[n]


n = 6
print(Fibonacci(n-1))
Output :

5

Method 2 : Using Recursion

Algorithm

  • Start by calling the function for n
  • If n is less then 2 return n
  • If n>0:
  • Return the sum of recursive call for same function with value  n – 1  &  n – 2

Python Code

Run 
def fib(n):
	if n < 2:
		return n
	return fib(n - 1) + fib(n - 2)


n = 6
print(fib(n-1))
Output :

5

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5 comments on “Find the Nth Term of a Fibonacci Series in Python”


  • boshinitp

    n = int(input(“enter a num: “))
    n1 = 0
    n2 = 1
    temp= 0
    l = [n1,n2]
    for i in range(2, n):
    temp = n1+n2
    l.append(temp)
    n1 = n2
    n2 = temp

    print(l[n-1])


  • manubhai28102005

    num = int(input(“Enter Num: “))

    n1 = 0
    n2 = 1
    arr = []
    arr.append(n1)
    arr.append(n2)

    for i in range(2,num):
    n3 = n1 + n2
    n1 = n2
    n2 = n3
    arr.append(n3)
    print(arr)


  • ncinthala

    n=int(input(‘enter the nth number ‘));
    temp=0;
    temp1=1;
    sum=0;
    arr=[];
    arr.append(temp);
    arr.append(temp1);
    for i in range(1,n-1):
    sum=temp+temp1;
    temp=temp1;
    temp1=sum;
    arr.append(sum);
    print(arr[n-1]);


  • sufiyashaik781

    def fib(N):
    if N==0:
    return []
    elif N==1:
    return [0]
    elif N==2:
    return [0,1]
    else:
    arr=[0,1]
    for i in range(2,N):
    n=arr[i-1]+arr[i-2]
    arr.append(n)
    return n
    N=int(input())
    print(fib(N))