Taking 2-2 Liters of Water

Solution for distribution of water

In order to find solution to this puzzle let us look at the given steps for a brief understanding.

1. At the initial state we have two bottles filled with 10 liters of water and one empty bottle of 4-liter and one empty bottle of 5-liter.
2. Now let us name first 10 liter bottle as A, 2nd 10 liter bottle as B , third 4-litre bottle as C and fourth 5-litre bottle as D.
3. We will transfer 5 liter water from Bottle B to Bottle D.
4. Now, transfer water from Bottle D to Bottle C.
5. Now, empty water from Bottle C to Bottle B which makes it 9 liters in it.
6. Transfer leftover water from Bottle D to C.
7. Transfer water from Bottle A to D, that makes 5 liters in both the bottles.
8. Now transfer the water from bottle D to Bottle C and make it full that is Bottle C = 4 liters filled.
9. Now Bottle D is left with 2 liters of water and therefore we achieve one bottle filled with only 2 liters of water.
10. Now transfer complete water from Bottle C, to Bottle B and make it completely full.
11. This way we are left with only 2 liters in Bottle C, 10 liters in Bottle B and 6 liters in bottle A.
12. Therefore, we have achieved 2nd bottle with 2 liters water only.

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