DXC Sample Papers and Model Questions and Answers 2019-2020

DXC Model Questions and Answers Latest 2019-20

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DXC Preparation Papers 2019 – Quants

 

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Q 1. Which one of the following is not a prime number?

A. 31

B. 61

C. 71

D. 91

Answer: Option D

Explanation:

91 is divisible by 7. So, it is not a prime number.

2. (112 x 54) = ?

A. 67000

B. 70000

C. 76500

D. 77200

Answer: Option B

3. What least number must be added to 1056, so that the sum is completely divisible by 23 ?

A. 2

B. 3

C. 18

D. 21

Explanation:

Answer: Option A

Explanation:

 23) 1056 (45

      92

      —

      136

      115

      —

       21

      —

 Required number = (23 – 21)   

                 = 2.  

4.  A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

A. 3.6

B. 7.2

C. 8.4

D 10

Answer: Option B

Explanation:

Speed = (600/5*60)m/sec =2m/sec.

=(2*18/15)Km/hr

7.2 km/hr.

5. An airplane covers a certain distance at a speed of 240 km in 5 hours. To cover the same distance in 1 hour, it must travel at a speed of:

A. 300kmph

B. 360kmph

C. 600kmph

D. 720kmph

Answer: Option D

Explanation:

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr.     [We can write 1 hours as 5/3 hours]

 Required speed =

 

1200 x

3

km/hr

= 720 km/hr.

5

6. A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

A. 1/4

B. 1/10

C. 7/15

D. 8/15

Answer: Option D

Explanation:

A’s 1 day’s work = 1/15

B’s 1 day’s work  = 1/20

(A + B)’s 1 day’s work = (1/15+1/20

(A + B)’s 4 day’s work = (7/60*4) = 7/15

Therefore, Remaining work =(1-7/15) = 8/15

7. Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

A. 24400

B. 21300

C. 210

D. 25200

Answer: Option D

Explanation:

Number of ways of selecting 3 consonants from 7
7C3
Number of ways of selecting 2 vowels from 4
4C2

Number of ways of selecting 3 consonants from 7 and 2 vowels from 4
7C3 × 4C2
=(7×6×53×2×1)×(4×32×1)=210=(7×6×53×2×1)×(4×32×1)=210

It means we can have 210 groups where each group contains total 5 letters (3 consonants and 2 vowels).

Number of ways of arranging 5 letters among themselves
=5!=5×4×3×2×1=120=5!=5×4×3×2×1=120

Hence, required number of ways
=210×120=25200

8.  In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

A. 159

B. 209

C. 201

D. 212

Answer: Option B

Explanation:

In a group of 6 boys and 4 girls, four children are to be selected such that at least one boy should be there.

Hence we have 4 options as given below

We can select 4 boys …(option 1)
Number of ways to this = 6C4

We can select 3 boys and 1 girl …(option 2)
Number of ways to this = 6C3 × 4C1

We can select 2 boys and 2 girls …(option 3)
Number of ways to this = 6C2 × 4C2

We can select 1 boy and 3 girls …(option 4)
Number of ways to this = 6C1 × 4C3

Total number of ways
6C4 + 6C3 × 4C1 + 6C2 × 4C2 + 6C1 × 4C3
6C2 + 6C3 × 4C1 + 6C2 × 4C2 + 6C1 × 4C1[∵ nCr = nC(n-r)]

=6×52×1+6×5×43×2×1×4=6×52×1+6×5×43×2×1×4 +6×52×1×4×32×1+6×4+6×52×1×4×32×1+6×4

=15+80+90+24=209

 9. Find the next number in the sequence:
3, 6, 9, 30, 117……

A. 192
B. 352
C. 388
D. 588

Answer: Option D

Explanation

3 * 1 + 3 = 6
6 * 2 – 3 = 9
9 * 3 + 3 = 30
30 * 4 – 3 = 117
117 * 5 + 3 = 588
 
10. A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
 
A. Rs.1000
B. Rs.1140
C. Rs.860
D. Rs.760
 

Answer: Option A

Explanation:

    90%

   104%

 ——–

     14% —- 140

 100% —- ? => Rs.1000

11. A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?

A. 21

B. 12

C. 9

D. 108

Answer: Option D

Explanation:

The boy can select one trouser in nine ways.

The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways.
 
12. How many three letter words are formed using the letters of the word TIME?
 
A. 12
B. 20
C. 16.
D. 24

Answer: Option D

Explanation:

The number of letters in the given word is four. 

The number of three letter words that can be formed using these four letters is ⁴P₃ = 4 * 3 * 2 = 24.
 
13. What number has a 5:1 ratio to the number 10?
 
A. 42
B. 50
C. 55
D. 62
 

Answer: Option B

Explanation:

5:1 = x: 10

x = 50

14. If a: b = 3:4, b:c = 7:9, c:d = 5:7, find a:d?

A. 5:12

B. 7:12

C.  3:11

D. 5:11

Answer: Option A

Explanation:

a/d = (3/4)*(7/9)*(5/7) => 5/12

15. The inverse ratio of 3: 2: 1 is?

A. 1:2:3

B. 2:3:1

C. 3:1:2

D. 2:3:6

Answer: Option D

Explanation:

1/3: 1/2: 1/1 = 2:3:6

 
 
 
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