Find maximum product sub-array in a given array

Maximum product of sub-array in Python

Here, in this page we will discuss the program to find the maximum product of sub-array in python programming language. We are given with an array and need to return the maximum value of the product of the sub-array.

Maximum product of sub-array in Python

Method Discussed

  • Method 1 : Brute Force solution
  • Method 2 : Efficient solution

Let’s discuss above two methods in brief.

Method 1 :

  • Create a variable say result, set result = arr[0], this variable hold the required maximum product.
  • Run a loop for range(n)
  • Create a variable mul = arr[i], this variable hold the product of sub-array.
  • Run a inner loop, set result = max(result, mul)
  • And, mul *= arr[j]
  • Update, result = max(result, mul)
  • Return result.

Time and Space Complexity :

  • Time Complexity : O(n2)
  • Space Complexity : O(1)

Method 1 : Code in Python

Run
def maxSubarrayProduct(arr, n):
 
    # Initializing result
    result = arr[0]
 
    for i in range(n):
     
        mul = arr[i]
       
        # traversing in current subarray
        for j in range(i + 1, n):
            result = max(result, mul)
            mul *= arr[j]
         
        # updating the result for (n-1)th index.
        result = max(result, mul)
     
    return result
 
arr = [ 1, -2, -3, 0, 7, -8, -2 ]
n = len(arr)
print("Maximum sub-array product is" , maxSubarrayProduct(arr, n))

Output

Maximum sub-array product is 112

Method 2 :

This is the efficient solution and is also similar to Largest Sum Contiguous Subarray problem which uses Kadane’s algorithm.

  • Declare three variables say max_so_far, max_ending_here & min_ending_here.
  • For every index the maximum number ending at that index will be the maximum(arr[i], max_ending_here * arr[i], min_ending_here[i]*arr[i]).
  • Similarly the minimum number ending here will be the minimum of these 3.
  • Thus we get the final value for maximum product subarray.

Time and Space Complexity :

  • Time Complexity : O(n)
  • Space Complexity : O(1)

Method 2 : Code in Python

def maxSubarrayProduct(arr, n):
    max_ending_here = arr[0];
    min_ending_here = arr[0];
    max_so_far = arr[0];
    
    for i in range(n):
        temp = max({arr[i], arr[i] * max_ending_here, arr[i] * min_ending_here});
        min_ending_here = min({arr[i], arr[i] * max_ending_here, arr[i] * min_ending_here});
        max_ending_here = temp
        max_so_far = max(max_so_far, max_ending_here)
    return max_so_far


arr = [ 1, -2, -3, 0, 7, -8, -2 ]
n = len(arr)
print("Maximum sub-array product is" , maxSubarrayProduct(arr, n))

Output

Maximum sub-array product is 112

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3 comments on “Find maximum product sub-array in a given array”


  • Vidyashree

    x=[1, -2, -3,0,7, -8, -2]
    y=[ ]
    mul=1
    for i in range(len(x)):
    for j in range(i,len(x)):
    mul=mul*x[j]
    y.append(mul)
    print(mul)
    mul=1

    print(“Maximum sub-array product is” , max(y))


  • Prashant

    arr=list(map(int,input().split()))
    sum=1
    for i in range(len(arr)):
    if arr[i]==0:
    pass
    else:sum*=arr[i]
    print(abs(sum))


    • nitesh

      list=[ 1, -2, -3, 0, 7, -8, -2 ,-2]
      multi,max=1,0
      for i in list:
      multi*=i
      if multi==0:
      multi=1
      if max<multi:
      max=multi
      print(max)