C++ program for Converting digit/number to words
Converting digit/number to words in C++
Here, in this page we will discuss the program for Digit/number to words in C++ .The conversion of numbers in words is just a conversion of numeric values to the English format of reading numbers. This code supports the conversion of numbers from 0 – 9999 in English format. Digits have different places when read from its ones place to above.
Different places for numbers are:-
Single digits:- OnesTwo Digits:-Tens
Three Digits:- Hundreds
Four Digits:- Thousands
Algorithm
- Taking input as a string from the user.
- Check the length of the input.
- if the length is zero print ’empty’ and if the length is greater than 4 print ‘give a string of specific length’
- if length id between 1 – 4, Create arrays for different values.
- Checking the length of the string.
- According to the place of the digit, we will show the output.
Code in C++
Run
#include<bits/stdc++.h>
using namespace std;
void
numToWords (string num)
{
int length_of_string = num.size ();
if (length_of_string == 0)
{
cout << "String is Empty";
return;
}
if (length_of_string > 4)
{
cout << "Please enter the string with supported length";
return;
}
string ones_digits[] =
{
"zero", "one", "two", "three", "four", "five", "six", "seven", "eight",
"nine"};
string tens_digits[] =
{
"", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"};
string multiple_of_ten[] =
{
"", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"};
string power_of_ten[] =
{
"hundred", "thousand"};
cout << num << ":\n";
if (length_of_string == 1)
{
cout << ones_digits[num[0] - '0'];
//return;
}
int x = 0;
while (x < num.size ())
{
if (length_of_string >= 3)
{
if (num[x] - 48 != 0)
{
cout << ones_digits[num[x] - 48] << "\n";
cout << power_of_ten[length_of_string - 3] << "\n";
length_of_string--;
}
}
else
{
if (num[x] - 48 == 1)
{
int sum = (num[x] - 48 + num[x] - 48);
cout << tens_digits[sum];
// return;
}
else if (num[x] - 48 == 2 and num[x + 1] - 48 == 0)
{
cout << "twenty"; //
return;
}
else
{
int i = num[x] - 48;
if (i > 0)
{
cout << multiple_of_ten[i] << " ";
}
else
{
cout << " ";
}
x += 1;
if (num[x] - 48 != 0)
{
cout << ones_digits[num[x] - 48];
}
}
}
x++;
}
}
int
main ()
{
numToWords ("1121");
return 0;
}
Output:
1121 : one thousand one hundred twenty one
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