Problem 33

March 8, 2021

18 comments on “Problem 33”


  • AJ.

    public static void main(String ard[]){

    Scanner sc=new Scanner(System.in);
    String s=sc.nextLine();
    String n[] = s.split(” “);

    System.out.print(String.join(” “,n));
    }


  • Daipayan

    import java.util.HashSet;
    import java.util.Scanner;

    /**
    * prep45
    */
    public class prep45 {

    public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    String str = sc.nextLine();
    HashSet set = new HashSet();
    int j = 0;
    for (int i = 0; i < str.length(); i++) {
    // System.out.println(str.charAt(i));
    if (str.charAt(i) == ' ') {

    set.add(str.substring(j, i+1));
    j = i;
    }
    if (i == str.length() – 1) {
    set.add(str.substring(j, i));
    }
    }
    for (String s : set) {
    System.out.print(s + " ");
    }
    }
    }


  • amit

    #include
    #include

    int main()
    {
    char arr[100];
    int k;
    scanf(“%[^\n]%*c”,arr);
    k=strlen(arr);
    // printf(“%s”,arr);
    for(int i=0;i<k;i++)
    {
    if(arr[i]!=' ' || arr[i+1]!=' ')
    printf("%c",arr[i]);
    }
    return 0;
    }


  • Sunny

    #Python3

    st=[]
    st1=input()
    for i in st1.split():
    st.append(i)
    for i in st:
    print(i,end=” “)


  • Gourab

    //Write a function that removes all duplicate spaces from a sentence. Your program should ensure that only one space exists between words
    #include
    #include
    int main(){
    char s[200];
    gets(s);
    int len,i,k;
    for(len=0;s[len]!=’\0′;len++);
    for(i=1;i<len;){
    if(s[i-1]==' ' && s[i]==' '){
    for(k=i-1;k<len;k++){
    s[k] = s[k+1];
    }
    }
    else i++;
    }
    puts(s);
    return 0;

    }


  • Raviteja

    Java Code:
    import java.util.*;
    public class Solution{
    public static void main(String args[]) {
    Scanner sc=new Scanner(System.in);
    String s = sc.nextLine();
    System.out.println(s.replaceAll(“\\s+”,” “).trim());
    }
    }


    • Raviteja

      Note : \\s in print statement is fixed thing for this code. To avoid ambiguity you can also take reference variable for String as str instead of s
      String str = sc.nextLine();
      System.out.println(s.replaceAll(“\\s+”,” “).trim());


  • Raman

    def read_s(a,n):
    for i in range(n):
    if a[i]==” ” and a[i+1]==” “:
    for j in range(i,n-1):
    a[j]=a[j+1]
    a[n-1]=””
    print(“”.join(a))

    a=list(input())
    n=len(a)
    read_s(a,n)


  • Pogakula

    #python3
    def remspace(s):
    lis=[]
    wor = ”
    for i in s+’ ‘:
    if i!=’ ‘:
    wor+=i
    else:
    if len(wor)>=1:
    lis.append(wor)
    wor=”
    else:
    continue
    return ‘ ‘.join(lis)
    st=str(input(‘enter the string:\t’))
    print(remspace(st))


  • Akash

    python code :
    string = input()
    s = str()
    for i in string.split():
    s+=i+’ ‘
    print(s)


  • SYEDAPSANA A

    int main ()
    {
    char sent[100];
    gets(sent) ;
    char *p;
    p = strtok(sent, ” “) ;
    while(p! = NULL)
    {
    printf(“%s “,p) ; //leave a space after %s
    p = strtok(NULL, ” “) ;
    }
    return 0;

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