C++ Code for Polygon TCS Codevita
Coding Question 4
In this article, we will discuss about the TCS CodeVita Coding Question which is asked in the TCS placement test along with a detailed solution. This will help you excel your coding problems.
Polygon Coding Question
Problem Description:
You are given N number of coordinates and you have to create a polygon from these points such that they will make a polygon with maximum area.
Note: coordinates provided in the input may or may not be in sequential form.
Constraints
1 <= N <= 10
Input:
First line contains an integer N which depicts number of co-ordinates
Next N lines consist of two space separated integer depicting coordinates of in form of xy
Output:
Print the maximum possible area possible by creating a polygon by joining the coordinates.
If the area is in decimal form, print the absolute value as output.
Time Limit (secs):
1
Examples:
Input:
4
0 0
2 0
0 2
2 2
Output:
4
Explanation:
As we can imagine that these points will make a square shape and the maximum possible area made by the polygon will be 4.
#include<bits/stdc++.h> using namespace std; struct Point { int x, y; }; // Comparator function to sort points based on x-coordinate (and y-coordinate in case of a tie) bool comparePoints(const Point &a, const Point &b) { return (a.x < b.x) || (a.x == b.x && a.y < b.y); } // Cross product of vectors (p1-p0) and (p2-p0) int crossProduct(const Point &p0, const Point &p1, const Point &p2) { int x1 = p1.x - p0.x; int y1 = p1.y - p0.y; int x2 = p2.x - p0.x; int y2 = p2.y - p0.y; return x1 * y2 - x2 * y1; } // Graham's Scan algorithm to find the convex hull vectorconvexHull(vector &points) { int n = points.size(); if (n <= 3) return points; // Sort the points based on x-coordinate (and y-coordinate in case of a tie) sort(points.begin(), points.end(), comparePoints); // Initialize the upper and lower hulls vector upperHull, lowerHull; // Build the upper hull for (int i = 0; i < n; i++) { while (upperHull.size() >= 2 && crossProduct(upperHull[upperHull.size() - 2], upperHull.back(), points[i]) <= 0) { upperHull.pop_back(); } upperHull.push_back(points[i]); } // Build the lower hull for (int i = n - 1; i >= 0; i--) { while (lowerHull.size() >= 2 && crossProduct(lowerHull[lowerHull.size() - 2], lowerHull.back(), points[i]) <= 0) { lowerHull.pop_back(); } lowerHull.push_back(points[i]); } // Combine the upper and lower hulls to get the convex hull upperHull.pop_back(); // Remove the last point to avoid duplication lowerHull.pop_back(); upperHull.insert(upperHull.end(), lowerHull.begin(), lowerHull.end()); return upperHull; } // Calculate the area of a polygon double calculateArea(vector &polygon) { int n = polygon.size(); if (n < 3) return 0.0; // Not a valid polygon double area = 0.0; for (int i = 0; i < n; i++) { int x1 = polygon[i].x; int y1 = polygon[i].y; int x2 = polygon[(i + 1) % n].x; int y2 = polygon[(i + 1) % n].y; area += (x1 * y2 - x2 * y1); } return abs(area) / 2.0; } int main() { int n; cin >> n; vector points(n); for (int i = 0; i < n; i++) { cin >> points[i].x >> points[i].y; } vector convexHullPoints = convexHull(points); double maxArea = calculateArea(convexHullPoints); cout << maxArea << endl; return 0; }
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