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# Robert Bosch Sample Paper and Model Question 2019-2020

### Robert Bosch Sample Question and Answer Latest

In this particular dashboard you will find the latest Robert Bosch Sample paper along with model Questions.In this page Robert Bosch sample paper has been classified into different sections for your better prepration.

### Robert Bosch PrepSter Paid Materials 2019 PDF

### Robert Bosch Sample Questions and Practice Papers

- Total Number of Questions asked: 10 Questions.
- Total Time Allotted: 5-8 mins
- Difficulty Level: Moderate

Click here to visit Robert Bosch Aptitude Preparation Paper Section

**Model Questions:**

Q.1-There is a leak in the bottom of the tank. This leak can empty a full tank in 8 hours. When the tank is full, a tap is

opened into the tank which admit 6 liters per hour and the tank is now emptied in 12 hours. What is the capacity of the

tank?

a.) 8.8 liters

b.) 36 liters

c.) 144 liters

d.) Cannot be determined

Answer-C

solution-

Since the leak can empty the tank in 8 hours,

In one hour, part of the tank emptied by the leak = 1/8

Also, after opening the tap, in one hour, part of the tank emptied = 1/12

Let the tap can fill the tank in x hours. Therefore, In one hour, part of the tank filled by the tap = 1/x

As per question, (1/x) – (1/8) = 1/12

Or x = 24

Since the tap admits 6 liters of water per hour, it will admit (6*24) =144 liters of water in 24 hours, which should be the

capacity of the tank.

Q.2-The HCF of two numbers is 29 & their sum is 174. The possible numbers are

a.) 1,174

b.) 74,100

c.) 29,145

d.) None of these

Solution-C

Let the numbers be 29a and 29b. Then, 29a + 29b= 174 or 29(a + b) = 174 or, a + b = 174/29 = 6. Values of co-primes

(with sum 6) is(1, 5).

So, the possible pairs of numbers is (29 x 1, 29 x 5) i.e. 29 and 145, which will become the answer.

Q.3)-A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture

at Rs. 30 per kg. His profit percent is:

a.)-No profit, no loss

b.)- 5%

c.)-8%

d.)-10%

Solution-B

C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.

S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.

Gain =(80/1600*100) % = 5%

Q.4-In one hour, a boat goes 11km along the stream and 5 km against it. Find the speed of the boat in still water?

a.) -6

b.)-7

c.)-8

d.)-9

Solution-C

We know we can calculate it by 1/2(a+b)

=> 1/2(11+5) = 1/2(16) = 8 km/hr

Q.5-Which of the following is not a prime number?

a.)-31

b.)-61

c.)-71

d.)-91

Solution-D

91 is divisible by 7. So it is not a prime number.

Q.6-A and B can do a piece of work in 6 2/3 days and 5 days respectively. They work together for 2 days and then A

leaves.?

In how many days after that B will complete the work alone.

a.)-2 days

b.)-3 days

c.)- 1 ½ days

d.)-3 ½ days

Solution-B

3/20 * 2 + (2 + x)/5 = 1

x = 1 ½ days

Q.7-The distance between two stations A and B is 778 km. A train covers the journey from A to B at 84 km per hour and

returns back to A with a uniform speed of 56 km per hour. Find the average speed of train during the whole journey?

a.)-60.3 Km/hr

b.)-35.0 Km/hr

c.)-57.5 Km/hr

d.)-67.2 Km/hr

Solution-D

Average Speed=(2xyx+y)

“>Average Speed=(2xy/x+y)

km/hr

=(2×84×5684+56)

“>=(2×84×5684+56)=(2×84×5684+56)

=(2×84×56140)

“>=(2×84×56140)=(2×84×56140)

=67.2 km/hr

“>=67.2 km/hr

Q.-8-If x^{3} + y^{3} = 9 and x + y = 3, then the value of x^{4}+y^{4} is,?

a.)-21

b.)-17

c.)-0

d.)-25

Solution-B

Average Speed=(2xyx+y)

“>Average Speed=(2xyx+y)Average Speed=(2xyx+y)

km/hr

=(2×84×5684+56)

“>=(2×84×5684+56)=(2×84×5684+56)

=(2×84×56140)

“>=(2×84×56140)=(2×84×56140)

=67.2 km/hr

“>=67.2 km/hr

Q.9-The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels

occupy the even places?

a.)-720

b.)-144

c.)-120

d.)-204

Solution-B

The word MEADOWS has 7 letters of which 3 are vowels.

let ratio be x.

Hence no. of coins be 5x ,9x , 4x respectively

Now given total amount = Rs.206

=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206

we get x = 40

=> No. of 50p coins = 200

=> No. of 25p coins = 360

=> No. of 10p coins = 160

- Total Number of questions : 10 Ques
- Total Time Allotted : 5-8 Mins
- Difficulty Level: Easy to Moderate

Click here to visit Robert Bosch Verbal Preparation Paper Section

**Model Questions:**

^{o}water in south pacific, we could still see our frosty breath inside the command module.

- Total Number of Questions asked: 10 Questions.
- Total Time Allotted: 10 mins
- Difficulty Level : Moderate

Click here to visit Robert Bosch Reasoning Preparation Paper Section

**Model Questions:**

Clearly, the word can be obtained by moving the letters at even-numbered positions in the code, three steps forward and omitting those at odd-numbered positions.

Thus

Q.4.

Insert the missing number.

7, 26, 63, 124, 215, 342, (….)

a.)-391

b.)-421

c.)-481

d.)-511

Solution-D

Numbers are (2^{3} – 1), (3^{3} – 1), (4^{3} – 1), (5^{3} – 1), (6^{3} – 1), (7^{3} – 1) etc.

So, the next number is (8^{3} – 1) = (512 – 1) = 511.

Q.5-

*.*

- T is to the immediate left of P and third to the right of U.
- V is the immediate neighbour of M and N and third to the left of S.
- M is the second to the right of Q, who is at one of the ends.
- R is sitting next to the right of P and P is second to the right of O.

Who is sitting in the center of the row?

a.)-N

b.)-O

c.)-S

d.)-U

Solution-D

The arrangement of the persons is

Q W M V N U S O T P R

U is sitting in the center of the row.

Q.6-** **Which of the following people are sitting to the right of S?

a.)-OTPQ

b.)-OTPR

c.)-UNVM

d.)-UOTPR

Solution-B

The arrangement of the persons is

Q W M V N U S O T P R

OTPR are sitting to the right of S.

Q.7-Which of the following statements is true with respect to the above arrangement?

a.)-There are three persons sitting between P and S

b.)-W is between M and V.

c.)- N is sitting between V and U

d.)-S and O are neighbours sitting to the immediate right of T.

Solution-C

The arrangement of the persons is

Q W M V N U S O T P R

Hence N is sitting between V and U.

Q.8-Who are the immediate neighbours of T?

a.)-O, P

b.)-O, R

c.)- V, U

d.)- N, U

Solution-A

The arrangement of the persons is

Q W M V N U S O T P R

O and P are the immediate neighbours of T.

Q.9-If Q and P, O and N, M and T, and W and R interchange their positions then which of the following pairs of friends is sitting at the ends?

a.)-P and Q

b.)-Q and R

c.)- P and W

d.)- W and R

Solution-C

The arrangement of the persons is

Q W M V N U S O T P R

If the persons as given in the question change their positions then we have the arrangement P R T V O U S N M Q W

Hence P and W are sitting at the ends.

Q.10-Choose the alternative which does not correspond to the given word.

VIBGYOR:

a.)-Olive

b.)-Yellow

c.)-Indigo

d.)-Red

Solution-A

O stand for orange is VIBGYOR.

- Total Number of Questions asked: 10-15 Questions.
- Total Time Allotted: 15 mins
- Difficulty Level : Moderate

Click here to visit Robert Bosch Technical(CSE) Preparation Paper Section

**Model Questions:**

Q.1-What will be output if you will compile and execute the following c code?

struct marks

{

int p:3;int c:3;

};

void main(){

struct marks s={2,-6};

printf(“%d %d”,s.p,s.c);

}

a.)- 2 -6

b.)-2 1

c.)- 2 2

d.)-Compile error

Solution-C

Exp: Binary value of 2: 00000010 (Select three two bit)

Binary value of 6: 00000110

Binary value of -6: 11111001+1=11111010

(Select last three bit)

Q.2-What will be output if you will compile and execute the following c code?

#include

Void main(){

printf(“%s”,”c” “question” “bank”);

}

a.)-C question bank

b.)- C

c.)-bank

d.)-Cquestion bank

Solution-D

In c string constant “xy” is same as “x” “y”

Q.3A Process Control Block(PCB) does not contain which of the following :-

a.)- Code

b.)- Stack

c.)- Bootstrap program

d.)- Data

Solution-C

Q.4-The wait-for graph is a deadlock detection algorithm that is applicable when :

a.)- all resources have a single instance

b.)- all resources have multiple instances

c.)- all resources have a single 7 multiple instance

d.)- all of the mentioned

Solution-A

Q.5-Which of the following is used to input the entry and give the result in a variable in a procedure?

a.)- Put and get

b.)- Get and put

c.)- Out and In

d.)- In and out

Solution-D

Create procedure dept count proc(in dept name varchar(20), out d count integer). Here in and out refers to input and result of procedure.

Q.6- A _________ consists of a sequence of query and/or update statements.

a) Transaction

b) Commit

c) Rollback

d) Flashback

Solution-A

Transaction is a set of operation until commit.

Q.7- What will be the output of following program ?

#include void main() { unsigned short var=’B’; var+=2; var++; printf(“var : %c , %d “, var,var);

a.)-var:E,69

b.)-var:E,68

c.)-var:D,68

d.)-var:D,69

Solution-A

unsigned short var=’B’; var has ASCII value of ‘B’ which is 66 var+=2 results to var=68 var++ results to var =69 which is ASCII value of ‘E’ thus its prints E when placeholder is %c & 69 when placeholder is %d

Q.8- What will be the output of following program ?

#include

void main()

{ int intVar=20,x; x= ++intVar,intVar++,++intVar; printf(“Value of intVar=%d, x=%d”,intVar,x); }

a.)-value of intVar=23,X=21

b.)-value of intVar=23,X=23

c.)-value of intVar=21,X=21

d.)-Error

Q.9-main()

{

char s[ ]=”man”;

int i;

for(i=0;s[ i ];i++)

printf(“\n%c%c%c%c”,s[ i ],*(s+i),*(i+s),i[s]);

}

Solution- mmmm

aaaa

nnnn

s[i], *(i+s), *(s+i), i[s] are all different ways of expressing the same idea. Generally array name is the base address for that array. Here s is the base address. i is the index number/displacement from the base address. So, indirecting it with * is same as s[i]. i[s] may be surprising. But in the case of C it is same as s[i].

Q.10- What are the characteristics of stateless server ?

a) Easier to implement

b) They are not fault-tolerant upon client or server failures

c) They store all information file server

d) They are redundant to keep data safe

Solution-A

- Total Number of Questions asked: 10 Questions.
- Total Time Allotted: 5-8 mins
- Difficulty Level: Moderate

Click here to visit Robert Bosch Technical(EC/EEE) Preparation Paper Section

Model Question

Q.1-Routing is done on which layer?

- Datalink Layer
- Network Layer
- Session
- Presentation

Solution:-B

Q.2-Which performs modulation and demodulation?

- Modem
- Fiber optic
- satellite
- Coaxial cable

Solution-A

Q.3-A discrete signal is said to be even or symmetric if x(-n) is equal to

a.)-X(n)

b.)-0

c.)-–x(n)

d.)- –x(-n)

Solution-A

Q4,-Which of the following time system operates with a continuous time signal & produces a continuous time output signal

a.)-Continuous time system

b.)-Discrete time system

c.)-Time invariant system

d.)-Time variant system

Solution-A

Q.5- Which of the following options defines the diode

a.)-Is the simplest of semiconductor devices

b.)-Has characteristics that closely match those of a simple switch

c.)- Is a two terminal device

d.)-All the above

Solution-D

Q.6- Which of the following elements are most frequently used for doping pure Ge or Si ?

a.)- Boron

b.)- Gallium

c.)-Indium

d.)- all the above

Solution-D

Q.7- In ADC 0808, which of the following pin enables high output

a.)- I/P0-I/P7

b.)-EOC

c.)-SOC

d.)-OE

Q.8-Which of the following is the conversion time of a dual-slope ADC

a.)-5 to 10 ns

b.)-10 to 100 ns

c.)- 100 to 200 ns

d.)-2 to 3 ns

Solution-C

Q.9- If a certain multiplexer can switch one of 32 data inputs to its output. How many different inputs does this MUX have?

a.)- 30 data inputs & 5 select inputs

b.)-32 data inputs and 5 select inputs

c.)- 32 data inputs and 4 select inputs

d.)-None of the above

Solution-B

32 data inputs and 5 select input as (25 = 32)

Q.10-__________ is known as fastest switching logic family

a.)-4 MHz

b.)-2 MHz

c.)-6 MHz

d.)-1 MHz

Solution-D

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