Pyramid number pattern
Pyramid number pattern
In this section, we learn how to print pyramid number pattern in the java.
here we create half pyramid, inverted half pyramid and the triangle pyramid using a number in java.
this pattern example are useful also in interview question in java, so see every step carefully of each pattern.
To create a simple number pattern using , you have to use two loop. Due to this, nested for loop define rows to create with the columns of the number.
The first for loop define the number of rows for the pattern. The second Loop prints each row with the number.
1. Write the Program to print the following pattern
Enter the row 5
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
Working
Step 1- first we need to initialize two variable for loop.
Step 2- The first loop work for the row. so loop work from 1 to row;
Step 3- The second loop work for the number in a row. so this loop work from 1 to i.
Step 4. Inside the second loop, print the j.
Step 5- Outside the second loop and inside the first loop, give new line.
Step 6- Stop.
C
JAVA
Python
C++
C
#include <stdio.h>
int main()
{
int i, j, n;
printf("Enter number of rows : ");
scanf("%d",&n);
for(i=1; i<=n; i++)
{
for(j=1; j<=i; j++)
{
printf("%d ",j);
}
printf("\n");
}
return 0;
}
JAVA
//java program to print pyramid of the number
import java.util.Scanner;
public class Main
{
public static void main(String[] args)
{
int i,j;
//Scanner class declaration
Scanner sc = new Scanner(System.in);
//input from user
System.out.print(" Enter the row");
int row = sc.nextInt();
//first loop for the row
for(i=1;i<=row;i++)
{
//second loop for print element in the row
for(j=1;j<=i;j++)
System.out.print(j+" ");
System.out.println();
}
}
}
Python
n=5
for i in range(n):
for j in range(i+1):
print(j+1,end=” “)
print()
C++
#include<iostream>
using namespace std;
int main()
{
int i, j, n;
cin>>n;
for(i=1; i<=n; i++)
{
for(j=1; j<=i; j++)
cout<<j;
cout<<endl;
}
return 0;
}
2. Write a program to print the following pattern
Enter number 5
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1
C
JAVA
Python
C++
C
#include <stdio.h>
int main()
{
int i, j, n;
printf("Enter number of rows : ");
scanf("%d",&n);
for(i=n; i>=1; i--)
{
for(j=1; j<=i; j++)
{
printf("%d ",j);
}
printf("\n");
}
return 0;
}
JAVA
//java program to print pattern
import java.util.Scanner;
public class Main
{
public static void main(String[] args)
{
int i,j;
//scanner class declaration
Scanner sc = new Scanner(System.in);
//input from user
System.out.print(" Enter the row");
int row = sc.nextInt();
//first loop for every new row
for(i=row;i>=0;i--)
{
//second loop to print number in the row
for(j=1;j<=i;j++)
System.out.print(j+" ");
System.out.println();
}
}
}
Python
n=5
for i in range(n):
for j in range(n-i):
print(j+1,end=” “)
print()
C++
#include<iostream>
using namespace std;
int main()
{
int i, j, n;
cin>>n;
for(i=n; i>=1; i--)
{
for(j=1; j<=i; j++)
{
cout<<j;
}
cout<<endl;
}
return 0;
}
3. Write a program to print the following pattern
Enter the row 5
1
2 3 2
3 4 5 4 3
4 5 6 7 6 5 4
5 6 7 8 9 8 7 6 5
C
JAVA
Python
C++
C
#include <stdio.h>
int main()
{
int n, i, j, k=0, s, count=0, count1=0;
printf("Enter number of rows : ");
scanf("%d",&n);
for(i=1; i<=n; i++)
{
for(s=1; s<=n-i; s++)
{
printf(" ");
count++;
}
while(k!=2*i-1)
{
if(count<=n-1)
{
printf("%d ",k+i);
count++;
}
else
{
count1++;
printf("%d ",i+k-2*count1);
}
k++;
}
count1 = count = k = 0;
printf("\n");
}
return 0;
}
JAVA
import java.util.Scanner;
public class Main
{
public static void main(String[] args)
{
int i,j,k=0,s,count=0,count1=0;
//scanner class declaratiom
Scanner sc = new Scanner(System.in);
//input from user
System.out.println("Enter the row");
int row = sc.nextInt();
//this loop work for the every new row
for(i=1;i<=row;i++)
{
//this loop is for spaces
for(s=1;s<=row-i;s++)
{
System.out.print(" ");
count++;
}
//while loop for print the number in the row
while(k!=2*i-1)
{
if(count<=row-1)
{
System.out.println((k+i)+" ");
count++;
}
else
{
count1++;
System.out.println((i+k-2*count1)+" ");
}
k++;
}
count1=count=k=0;
System.out.println();
}
}
}
Python
n=5
for i in range(n):
x=i+1
for j in range(2*n-1):
if(i+j<n-1 or i+j>=n+2*i):
print(” “,end=“”)
else:
print(x,end=“”)
if(j<n-1):
x+=1
else:
x-=1
print()
C++
#include <iostream>
using namespace std;
int main()
{
int n, i, j, k=0, s, count=0, count1=0;
cin>>n;
for(i=1; i<=n; i++)
{
for(s=1; s<=n-i; s++)
{
cout<<" ";
count++;
}
while(k!=2*i-1)
{
if(count<=n-1)
{
cout<<k+i;
count++;
}
else
{
count1++;
cout<<i+k-2*count1;
}
k++;
}
count1 = count = k = 0;
cout<<endl;
}
return 0;
}
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