Print Number Star Right Triangle Pattern Type1

March 17, 2022

PRINT PATTERN  1 2*3 4*5*6 7*8*9*10

For any input number N Print the following code – For below code N=4 
1
2*3
4*5*6
7*8*9*10

PREREQUISITE:

Basic knowledge in Java programming, usage of loops.

ALGORITHM:

  1. Take input from user i.e number of lines required (N value).
  2. Take two loops one for each line (say ‘i’) and other for each digit in a particular line (say ‘j’). i starts from 1 and j starts from 1.
  3. Take a result variable (say ‘a’) and initialize it with 1.
  4. Here ‘i’ loop is used to access each line from 1 to n and ‘j’ loop is used to print values in each line. j loop is executed until it reaches i value.
  5. Print ‘a’ value along with * and post increment  until the j loop reaches a value less than i.
  6. Print the final value ‘a’ of each line and go to next line.
  7. Repeat the ‘i’ loop until it reaches n.

CODE IN JAVA:

Run 
import java.lang.*;
import java.io.*;
class Main
{
    public static void main(String[] args)throws IOException
    {
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        int n, i, j, a = 1;
        System.out.print("Enter N value:");
        n=Integer.parseInt(br.readLine());
        
        for(i = 1; i <= n; i++)
        {
            for(j = 1; j < i; j++)
            {
                System.out.print((a++)+"*");
            }
            System.out.println(a++);
        }
    }
}

Enter N value:5
1
2*3
4*5*6
7*8*9*10
11*12*13*14*15

TAKING INPUT:

TAKING OUTPUT:

1 comments on “Print Number Star Right Triangle Pattern Type1”


  • 2100049006ece

    import java.util.*;
    public class pattern{
    public static void main(String[] args){
    Scanner sc=new Scanner(System.in);
    System.out.print(“enter number of rows=”);
    int n=sc.nextInt();
    int k=1;
    for(int i=0;i<n;i++){
    for(int j=0;j<=i;j++){
    if(j!=i){
    System.out.print(k+++"*");
    }
    else{
    System.out.print(k++);
    }
    }
    System.out.println();
    }
    }
    }