Java Program for Numbered Square Pattern

May 24, 2020

Printing Numbered Square Pattern

In this program we’re going to code a Java Program for printing number square star pattern.

The logic of this problem is to take a row and column input from user and store in the variable names as row and col and then take a for loop start from int i=1 i<=row and then take inner for loop start from j=1 to j<= col and then print 1 and then change the line

Java Program for Numbered Square Pattern

Algorithm:

  • Take number of rows/columns as input from the user and save it in any variable (‘row’ and ‘col’ in this case).
  • Run a loop ‘row’ number of times to iterate through the rows. From i=1 to i<=r.  The loop should be structured as for(int i=1 ; i<=row ; i++)
  • Run a nested loop inside the previous loop to iterate through the columns. From  j=1 to j<=col. The loop should be structured as for (int j = 1; j <= col; j++)
  • Inside the nested loop print ‘1’ to print ‘1′ in each column of a row.
  • Inside the main loop print a newline to move to the next line after a row. System.out.println();

Code in Java:

import java.util.Scanner;
public class Pattern1 {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		System.out.println("Enter row and col");
		int row = sc.nextInt();
		int col = sc.nextInt();
		for (int i = 1; i <= row; i++) {
			for (int j = 1; j <=col; j++) 
				System.out.print("1");
			System.out.println();
		}
	}

}
This code is contributed by Shubham Nigam (Prepinsta Placement Cell Student)

3 comments on “Java Program for Numbered Square Pattern”


  • Surya

    public static void main(String ar[])
    {
    Scanner obj=new Scanner(System.in);
    System.out.println(“enter the size”);
    int n=obj.nextInt();
    int i,j;

    for(i=0;i<n;i++)
    {
    for(j=0;j<n;j++)
    {
    System.out.print("1");
    }
    System.out.println();

    }


  • Khan

    //javascript

    function pattern() {
    let n = 4;
    for (let i = 0; i < n; i++) {
    let sum = " ";
    for (let j = 0; j < n; j++) {
    sum += 1;
    }
    console.log(sum);
    sum = " ";
    }
    }
    pattern();

    //pattern
    // 1111
    // 1111
    // 1111
    // 1111