C++ Program to find Permutations in which n people can occupy r seats in a classroom
Which n people can occupy r seats in a classroom in C++
This is a problem specific program which deals with problems like in how many ways employees can be arranged in the seats available in a company or the same for the students in a school or college.
This problem can be easily solved by the use of the simple formula of permutations which is
Formula = n P r = n! / (n-r)!
Problem Statement :
In a classroom some of the seats are already occupied by students and only a few seats are available in the classroom. The available seats are assumed as r and n number of students are looking for the seat. We need to find in how many different permutations n number of students can sit on r number of chairs.
Algorithm
- Input number of students in n
- Input number of seats in r
- Use permutation formula { factorial(n) / factorial(n-r) }
- Print Output
C++ code
//Permutations in which n people can occupy r seats
#include<iostream>
using namespace std;
//function for factorial
int factorial(int num)
{
int fact=1;
for(int i=num; i>=1 ;i--)
fact*=i;
return fact;
}
//main program
int main()
{
int n,r;
cout<<"Enter number of people: ";
//user input
cin>>n;
cout<<"Enter number of seats: ";
//user input
cin>>r;
//finding all possible arrangements of n people on r seats
// by using formula of permutation
int p = factorial(n)/factorial(n-r);
//printing output
printf("Total possible arrangements: %d",p);
return 0;
}
Output
Enter number of people: 5 Enter number of seats: 9 Total possible arrangements: 120
For similar question click on given button.
Prime Course Trailer
Related Banners
Get PrepInsta Prime & get Access to all 200+ courses offered by PrepInsta in One Subscription
Login/Signup to comment

#include
using namespace std;
int factorial(int num){
int fct=1;
for(int i=0;i>num1>>num2;
int k=factorial(num1)/factorial(num1-num2);
cout<<"The no of ways to arrange the "<<p<<" "<<endl;
return 0;
}
#include
using namespace std;
int permutation(int n, int r) {
if(n == 0 || r == 0) {
return 1;
}
return n*permutation(n-1, r)/permutation(n-r, r);
}
int main()
{
int num, p;
cout <<"Enter seats: " <> num;
cout <<"Enter people: " <> p;
cout << permutation(num,p) << "Hello" << endl;
return 0;
}
[…] Permutations in which n people can occupy r seats in a classroom : C | C++ | Java | Python […]