Print Number Star Right Triangle Pattern Type2
PRINTING PATTERN:
7*8*9*10
4*5*6
2*3
1
PREREQUISITE:
Basic knowledge of C language and use of loops.
ALGORITHM:
- Take the number of rows/columns as input from the user and store it in any variable.(‘r‘ in this case).
- Run a loop ‘r’ number of times to iterate through each of the rows. From i=0 to i<r The loop should be structured as for( i=0 ; i<r: i++).
- and add the ‘i’ value to count.
- Run another loop ‘r’ number of times to iterate through each of the rows. From i=0 to i<r The loop should be structured as for( i=0 ; i<r: i++).
- Reinitialise the value of count as count=count-r+1 then give the same value to count1
- Run a nested loop to iterate through the columns. From j=0 to j<r. The loop should be structured as for(j=0 ; j<r; j++).
- increment count and run an if condition if(j!=r).
- if true then print star and count else print only count.
- outside the nested loop print a newline
- Then give value of count1 to count
CODE IN C:
#include<stdio.h>
int main()
{
int i,j,r,count,count1; //declaring integer variables i,j for loops , r for number of rows and count for increment in value
count=0; //initialising count
printf("Enter the number of rows :\n"); //Asking user for input
scanf("%d",&r); //taking number of rows and saving it in variable r
for(i=1;i<=r;i++) //loop to calculate max value of count
{
count+=i; //incrementing count
}
for(i=0;i<r;i++) // loop for number of rows
{
count=count-r+i; //changing value of count
count1=count; //giving value of count to count1
for(j=r;j>i;j--) // loop for digits per each row
{
count++; //incrementing count
if(j!=r) //if condition to print star and digit
printf("*%d",count); //printng star and digit
else //else condition to print only digit
printf("%d",count); //printing digits
}
printf("\n"); //printing newline
count =count1; // giving count its original value
}
}

DISPLAYING OUTPUT:
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