Quiz-1

The answer sheets are work here. So
M1*D1*H1*W2 = M2*D2*H2*W1
11*15*6.5*3 = 6*29*H2*1
Solve, H2 = 18.49

In order to solve this sum we have to apply unitary method.

The formula is: [(no.of men)*(no.of days)*(no.of hours)]/(work).

Acc to the question, m1 = 14

w1 = 87.

d1 = 28.

m2 = 29.

d2 = 19.

w2 = ?

From the formula we can write, (14 * 29) / (87) = (29 * 19) / (w2)

or, w2 = (29 * 19 * 87) / (14 * 29)

or, w2 = 118.

Therefore, 29 men can reap 118 acres of land in 19 days

 

In a ranch, 22 horses eat 42 kgs of grass in 19 days. We have to calculate the days in which one horse eat 1 kg of grass.
Let a number of days be \'x\' .
Solution:
22 horses : 42 kgs : 19 days =  1 horse : 1 kg : x days
22 : 42 : 19 = 1 : 1 : x
22 / 42 : 19 = 1 / 1 : x
0.52 : 19 = 1 : x
0.52 / 19 = 1 / x
x = 36.5
which shows that 1 cows will eat 1 bag of husk in 20 days.

 

Let x be the required length of the wall.

More men means more work will be done. (Therefore, Amount of work is directly proportional to Number of men)

Less days means less length built. (Therefore, number of days of work is directly proportional to length of wall built)

Men: 30   40  : 56 meters

Days: 5     3    : x meters

Therefore, we have:

Miguel raised $2,372.50 in 36.5 weeks

Amount raised in one week is

=  2372.5 / 36.5

=  $65

Amount raised in 20 weeks is

=  65 ⋅ 20

=  $1300

Hence, the money raised in 20 weeks is $1300

Because, less number of basket balls -----> cost will be less
Given : 75 basketballs cost $1,143.75
Cost of one basket ball = 1143.75 / 75 = 15.25
Then, cost of 26 basket balls = 15.25 x 26 = 396.50
Hence, the cost of 26 basket balls is $ 396.50

Given that fort had provision for 500 persons for 27
days
Hence, after 3 days, the remaining food is sufficient for 500 persons for 24
days

Remaining persons after 3 days = 500 + 300 = 800
Assume that after 10 days,the remaining food is sufficient for 800 persons for x
days

More men, Less days (Indirect Proportion)
⇒Men500:800}::x:24
⇒500×24=800x⇒5×24=8x⇒x=5×3=15

Let the required number days be x.

Less spiders, More days (Indirect Proportion)

Less webs, Less days (Direct Proportion)

Spiders1:7Webs7:1}⋮⋮ 7:xSpiders1:7Webs7:1⋮⋮ 7:x

=> 1 * 7 * x = 7 * 1 * 7

=> x= 7

Let the required number of days be x.

Less cows, More days (Indirect Proportion)

Less bags, Less days (Direct Proportion)

Cows	1	:	40		:: 40 : x
Bags	40	:	1