Robert Bosch Simple Interest Compound Interest Quiz 3

Let Principal Amount be P
Amount = 4P, T = 22 years

S.I = 4P - P = 3P
Therefore, Rate = \frac{100 \times S.I}{P \times T}
Rate = \frac{100 \times 3P}{P \times 22}
= 13.63 %

Let principal = P
Therefore, S.I = 0.225 P, Rate = 12 %
Since, S.I = \frac{P\times R\times T}{100}
0.225 P = \frac{P\times 12\times T}{100}
0.225P\times 100 = P \times 12\times T<br /> T = \frac{0.225\times100}{12}
T = 1.8 Years

Let the total investment in scheme B be Rs. X, then
[(50000-X)\times\frac{10}{100}] + [X \times(\frac{15}{100})] = 5000
\frac{250000-5X+12X}{100} = 5000
\frac{250000+7X}{100} = 5000
7X = 250000
X = \frac{250000}{7}
X = 35714.28 Rs

Here, Simple Interest earned from X mutual fund
= \frac{20000\times10\times3}{100}
= 6000 Rs
Now, Simple Interest earned from Y mutual fund
= \frac{6000\times15\times4}{100}
= 3600 Rs
Therefore, Simple Interest Earned = 6000+3600=Rs9600

Let the sum be Rs X
S.I = \frac{1}{4}X
Now, Let rate be R% and time = R years
S.I = \frac{P\times R\times T}{100}
\frac{X\times R\times R}{100}= \frac{1}{4}X
R^{2} = \frac{100}{4}
R = \frac{10}{2}
R = 5

Given, Principal = Rs 6000, Rate = 8 %, Time = 2 years
Using Formula: Amount = P(1+\frac{r\times t}{100})
Amount = 6000(1+\frac{8\times 2}{100})
Amount = 6000(1+\frac{16}{100})
Amount = 6000(\frac{116}{100})
Amount = Rs 6960

Given, Principal = 8000 Rs, Interest = 850 Rs, Rate of interest = 10 %
Since , S.I = (\frac{P\times R \times T}{100})
850= (\frac{8000\times 10 \times T}{100})
T = \frac{850\times100}{8000\times10}
T = 1 Years

Principal = Rs 680
Interest = Rs 190
Time = 6 months
i.e. Time = \frac{1}{2} years
Using the formula,
RateOfInterest = \frac{I\times100}{P\times T}
RateOfInterest = \frac{190\times100}{680\times \frac{1}{2}}
RateOfInterest = \frac{190\times100}{340}
Rate of Interest = 55.8 %

Let, Sum be Rs. X
Amount = Rs 5550
Number of years = 8 years
Interest Rate = 6 %
Using Formula , Amount = P(1+ \frac{R\times T}{100}) for finding P
Amount = P(1+ \frac{R\times T}{100})
5550 = P(\frac{37}{25})
P = \frac{5550\times25}{37}
P = 3750 Rs
Required Amount = P(1+\frac{R\times T}{100})
Required Amount = 3750(1+\frac{12\times 5}{100})
Required Amount = 3750(\frac{8}{5})
Required Amount = Rs 6000

After 3 years the amount is 4500 and in the next 2 years it becomes Rs. 5200.
Given, P = Rs 4500
Amount = Rs 5200
Interest = 5200 - 4500 = Rs 700
Years = 2 Years
\text{Rate Of Interest} = \frac{I\times100}{P\times T}
\text{Rate Of Interest} = \frac{700\times100}{4500\times 2}
Rate Of Interest = 7.7 %