Quiz – 1

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Question 1

Time: 00:00:00
If the distance between the points (3, k) and (4, 1) is , then the value of k is

4 or 2

4 or 2

- 4 or –2

- 4 or –2

-4 or 2

-4 or 2

4 or –2

4 or –2

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Question 2

Time: 00:00:00
The point on the y-axis which is equidistant from A(–5, –2) and B(3, 2) is

(4, –2)

(4, –2)

(1, –2)

(1, –2)

(0, –2)

(0, –2)

(2, –2)

(2, –2)

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Question 3

Time: 00:00:00
The vertices of a triangle are (–2, 0), (2, 3) and (1, –3), then the type of the triangle is

Right angle

Right angle

Equilateral

Equilateral

Isosceles

Isosceles

Scalene

Scalene

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Question 4

Time: 00:00:00
The points which are not collinear are  (I) (0, –1), (8, 3) and (6, 7)  (II) (4, 3), (5, 1) and (1, 9)  (III) (2, 5), (–1, 2) and (4, 7)  (IV) (–3, 2), (1, –2) and (9, –10)

I

I

b. II

b. II

c. III

c. III

d. IV

d. IV

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Question 5

Time: 00:00:00
The coordinates of the point which divides the line segment joining the points (–7, 4) and  (–6, –5) internally in the ratio 7 : 2 is

(−54/9,−3)

(−54/9,−3)

(−56/9,−3)

(−56/9,−3)

(−56/9,−6)

(−56/9,−6)

(−53/9,−3)

(−53/9,−3)

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Question 6

Time: 00:00:00
If the coordinates of the centroid of a triangle are (1, 3) and two of its vertices are (–7, 6) and  (8, 5), then the third vertex of the triangle is

(23,143)

(23,143)

(–2, -2)

(–2, -2)

(2,- 2)

(2,- 2)

(–2, 2)

(–2, 2)

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Question 7

Time: 00:00:00
The ratio in which the line segment joining (3, 4) and (–2, –1) is divided by the x-axis is

1:2

1:2

4:2

4:2

1:3

1:3

none

none

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Question 8

Time: 00:00:00
If a line passes through the mid-point of the line joining (–3, –4) and (–5, 6) and has a slope of 3434 , then its equation is

3x / 4y + 16 = 0

3x / 4y + 16 = 0

3x – 4y + 16 = 0

3x – 4y + 16 = 0

3x + 4y - 16 = 0

3x + 4y - 16 = 0

3x + 4y + 16 = 0

3x + 4y + 16 = 0

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Question 9

Time: 00:00:00
The equation of the line through (2, –4) and parallel to the line joining the points (2, 3) and (–4, 5) is

3x – y = 0

3x – y = 0

x + 3y = 0

x + 3y = 0

x + 3y + 10 = 0

x + 3y + 10 = 0

3x – y = 14

3x – y = 14

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Question 10

Time: 00:00:00
If the vertices of a triangle are (1, 3), (–2, 4) and (3, –5), then the equation of the altitude from (1, 3) to  the opposite side is

9x + 5y – 24 = 0

9x + 5y – 24 = 0

9x – 5y + 24 = 0

9x – 5y + 24 = 0

5x – 9y + 22 = 0

5x – 9y + 22 = 0

5x + 9y – 22 = 0

5x + 9y – 22 = 0

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["Need more practice!","Keep trying!","Not bad!","Good work!","Perfect!"]