Reliance Jio Averages Quiz 1

Average = 0

Therefore, the sum of 20 numbers= 0 x 20 =0

19 numbers among them may be positive.

If the sum of these numbers is a, then the 20th number is –a.

A + B = 5050 x2 = 10100 -----(i)

B + C = 6250 x 2 = 12500-----(ii)

C + A = 5200 x 2 = 10400-----(iii)

Adding the above three equations, we get,

2 (A + B + C) = 33000

Or, A + B + C = 16500-----(iv)

When we subtract (ii) from (iv), we get

A = 4000

Therefore, A’s monthly income = Rs. 4000

Average = Total runs/ Total innings

Total= 31 x 9 = 279

Needed increased average =4

New average = 31 +4 = 35 runs

Total runs = 35 x 10 = 350

Runs made in the next inning = 350 – 279 = 71.

We can say that, (3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x )/ 12 = 12.

=> 137 + x= 144

=> x = 144 – 137

=> x= 7

The removed number is = (25 x 5) – (23 x 4) = 125 - 92 = 33

Family average age = (67∗2+35∗2+6∗3)/(2+2+3)

= (134+70+18)/7

= 222/7

= 31.71

Let the average expenditure be Rs. x Then,

9x=[(8*30)+(x+20)]

=>9x =x+260

=> x =32.50

Total money spent = 9x = Rs. (9 x 32.5O) = Rs 292. 50

M + Tu + W + Th = 4 x 48 = 192
Tu + W + Th + F = 4 x 46 = 184
M = 42
Tu + W + Th = 192 - 42 = 150
F = 184 – 150 = 34

Average = total runs / no.of innings = 32

So, total = Average x no.of innings = 32 x 10 = 320.

Now increase in avg = 4runs.
So, new avg = 32+4 = 36runs

Total runs = new avg x new no. of innings = 36 x 11 = 396

Runs made in the 11th inning = 396 - 320 = 76

Let us assume the first number as f.

Therefore, the sum of the four numbers = f + 4f = 5f

=> 5f/4 = 40

=> 5f = 160

=>f= 32