# Automorphic number using Python

## Check Whether or Not the Number is an Automorphic Number in Python

Given an integer input for a number, the objective is to check whether or not the number is Automorphic or not. Therefore we’ll write a program to Check Whether or Not the Number is an Automorphic Number in Python Language.

```Example
Input : 5
Output : It's an Automorphic Number.
```

## Check Whether or Not the Number is an Automorphic Number in Python Language

Given an integer input as the number the objective is to check whether or not the number is an Automorphic number. To do we’ll first square the number and check if the number has been repeated in the same order of digits at the end of it’s square. For a Number to be Automorphic, it must pass the below mentioned condition

Therefore, to Check Whether or Not a Number is an Automorphic Number, we write a Python Code using the following methods –

• Method 1: Using Modulo Operators
• Method 2: Short cut
• Method 3: Using endswith() method

We’ll discuss the above-mentioned methods in detail in the upcoming sections.

### Working

In this method we’ll use the modulo operator to extract the last number of digits based on the length of the number input. We’ll reverse the number to match with the original numeric order of the digits.

Given an integer input as the number, we perform the following operations,

• Find the square of the given integer input.
• Check is the square % 10 ** len( str( number ) ) matches the original number itself.

Let’s implement the above Logic in Python Language.

### Python Code

Run
```number = 376
square = pow(number, 2)
mod = pow(10, len(str(number)))

# 141376 % 1000
if square % mod == number:
print("It's an Automorphic Number")
else:
print("It's not an Automorphic Number")```

### Output

```it's an Automorphic Number
```

## Method 2 : One Line Method (using Slicing)

Run
```# One line method for automorphic number in python
n = 376
# n^2 = 141376 141376[-3::] = 376
print("YES" if int(str(n**2)[-len(str(n))::]) == n else "No")```

`YES`

## Method 3 : Using Endswith() Method

The `endswith()` method returns True if the string ends with the specified value, otherwise False.
Run
```num = 376
a = str(num)

num1 = num ** 2
b = str(num1)

if b.endswith(a):
print("It's an Automorphic Number")
else:
print("It's not an Automorphic Number")
```

### Output

```It's an Automorphic Number
```

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### 19 comments on “Automorphic number using Python”

• Srikanth

# easy way
num =int(input(“Enter the number : “))
a = str(num)
num1=num**2
b=str(num1)
if b.endswith(a):
print(“Arthomarphic”)
else:
print(“not a Arthomarphic”)

• Mohammed

def auto(num):
sq = str(num*num)
print(sq)
l = len(str(num))
if sq[-l:] == str(num):
return f”{num} is Automorphic number”
else:
return f”{num} is not a Automorphic number”

n = int(input(“Enter the number: “))
print(auto(n))

• Dnyaneshwari

num=int(input(“enter the number: “))
digit=num**2
a_num=digit%10
if(a_num==num):
print(“automorphic”)
else:
print(“not automorphic”)

• baishakhibehera14

#program to chk automorphic no
#logic:
#if last digits of square of n==n,yes
n=int(input(“enter the no”))
N=n*n
N1=str(N)
N2=N1[-2:]
N3=int(N2)
if n==N3:
print(“yes”)

• rahul

no = input()
fno = int(no)
square = str(fno * fno)
if square.endswith(no):
print(‘automorphic number’)
else:
print(‘not automorphic’)

This code works out!

• Ashish

n=int(input(“Enter Number”))
sq=n*n
a=str(n)
b=str(sq)
l1=list(a)
l2=list(b)
if a in l2:
print(“automorphic number “)
else:
print(“Non automorphic number”)

• kaushiki

num = int (input(“Enter the number”))
square = num*num
if(num%10==square%10):
print(“Number is Automorphic”)
else:
print(“Number is not Automorphic”)