Quiz-1

A 5 litre jug contains 4 litres of a salt water solution that is 15 percent salt. If 1.5 litres of the solution spills out of the jug,then 2.5 ltrs of solution with 15% salt is left in jug.

If solution is now increased to 5 ltrs, the volume is doubled, then salt percentage is halved to 7.5%.

Deep=D let D= {20}
Mohan=2D--> 2*D= {40}
Yogesh= 3+(D/2) --> 3+(20/2)= {13}
M>D>Y
hence can't b determined

(x+.07x)=2468
1.07x=2468
x=2306
reduce=2468-2306=162
ans)162

50
increase in 1 share = Rs. 0.25
increase in x shares =Rs.12.50
so x=12.50/0.25 =50

40%
let d price of a ticket be Rs.100, so 3tickets cost 300 & 5tickets cost 500
5tickets purchased at price of 3 tickets ie., for 300, so amount saved s Rs.200,
% of 5 tickets = (200 /500)*100 =40 %

400
total marks:1500 for three exams
60% of 1500=900
first exam marks=45% of 500=225
second exam marks=55% of 500=275
let X be the third exam marks
225 + 275 + X =900
X=400

24,000. population - 3,00,000, males -1,80,000, females-1,20,000
50%of 3,00,000 literate - so 1,50,000 literate
70% of 1,80,000 literate -so 1,26,000 male literates , so rest s
1,50,000 - 1,26,000 = 24,000

Let the quantity of the wine in the cask originally be x litres. 8 litres of wine is removed from it and replaced with water. This operation is done total 4 times. After 4 operation,

Wine : Water = 16 : 65 or Wine : Total = 16 : 81

[(x-8)/x]⁴ = 16/81

(x-8)/x = 2/3

3x - 24 = 2x

x = 24

The correct answer is (b) i.e. Rs.200

(1-(1/16))(1-(1/15))(1-(5/7)) of Income = 50

Hence income = 200

Given ratio is 7:6;
let weight before and after reduction be 7x and 6x respectively.
A/Q
7x=56.7
=> x=56.7/7
=> x= 8.1
Reduced weight= 6x= 6*8.1= 48.6;
hence reduced weight= 48.6

7:5
if birds on 1st branch=x, 2nd branch=y
Ist condition, x-1=y+1, x-y=2 ---(i) &
2nd condition, x+1=2(y-1), x-2y=-3 ---(ii)
Solving (i) & (ii), x=7, y=5