GGK Technologies Model and Sample Papers 2019

Ques 5- He admired the speed with which he completed the work and appreciating the method adopted by him

a) appreciate the method being adopted
b) appreciated the method adopted
c) appreciate the method of adoption
d) appreciated the method adopting method
e) No correction required

Answer: Option B

Ques 6- Acquisition of certain specific skills can be facilitated from general awareness, education to novel situations

a) can be facilitated by
b) may facilitate through
c) can be felicitated with
d) may be felicitated with
e) No correction required

Answer: Option A

Ques 7-They should have calmly thought of the advantages that would accrue to them.

a) should have been calm in thinking about
b) should be calmly thought of
c) shall have to calmly thought of
d) should have calmly think of
e) No correction required

Answer: Option E

Ques 4- Here are some words translated from an artificial language.
briftamint means militant
uftonel means occupied
uftonalene means occupation
Which word could mean “occupant”?

a) elbrifta
b) uftonamint
c) elamint
d) briftalen

Answer & Explanation
Answer: Option B

Explanation:

Brift means the root word mili–; the suffix amint means the same as the English suffix –tant; the root word ufton– means occupy; el means the suffix –ied of occupied; and alene means the suffix –tion. (Because ufton means occupy, choices a, c, and d can be easily ruled out.)

Ques 5-Raju weighs less than Farhan.
Raju weighs more than Bunty.
Of the three friends, Bunty weighs the least.
If the first two statements are true, the third statement is

a) True
b) False
c) Uncertain

Answer & Explanation

Sol: OptionA
According to the first two statements, Farhan weighs the most and Bunty weighs the least.

Ques 6-Find the next number in the sequence….

15, 31, 63, 127, 255.
a) 110
b) 170
c) 511
d)181
Answer & Explanation

Sol: Option C
15 * 2 + 1 = 31
31 * 2 +1 = 63
63 * 2 + 1= 127
127 * 2 + 1= 255
255 * 2 + 1 = 511

Ques 7- John has more coins than Sonu.
Sonu has fewer coins than Danish.
Danish has more coins than John.
If the first two statements are true, the third statement is
a) True
b) False
c) Uncertain

Answer & Explanation

Sol: Option B
If the first two sentences are true, both John and Danish have more coins than Sonu. However, it is uncertain as to whether Danish has more coins than John.

Time – 10 Mins

Questions – 11 Ques

Model Questions:-

Ques 1-#include
int main()
{
printf(“%d”, printf(“%d”, printf(“%d”, printf(“%s”, “Welcome to prepinsta”))));
return (0);
}

a) Welcome to prepinsta2421
b) Welcome to prepinsta2124
c) Welcome to prepinsta3125
d) welcome to prepinsta2531

The answer is (b)

Explanation : As we all know that the printf function returns the numbers of character that is going to print and scanf function returns the number of input given.

Ques 2-What will be the output of following program?

#include

using namespace std;
int main()
{
int x = 5;
if(x==5)
{
if(x==5) break;
cout<<“Hello”;
}

cout<<“Hi”;
}

a) Compile error
b) Hi
c) HelloHi
d) Hello

Answer : a
Explanation: Compile error, keyword break can appear only within loop/switch statement.

Ques 3- What will be the output of following program?

#include
using namespace std;
int array1[] = {1200, 200, 2300, 1230, 1543};
int array2[] = {12, 14, 16, 18, 20};
int temp, result = 0;
int main()
{
for (temp = 0; temp < 5; temp++) {
result += array1[temp];
}
for (temp = 0; temp < 4; temp++) {
result += array2[temp];
}
cout << result;
return 0;
}

a) 6553
b) 6533
c) 6522
d) 12200

Answer : B
Explanation: In this program, we are adding the every element of two arrays. Finally we got output as 6533. Means for first array total sum will be 1200 + 200 + 2300 + 1230 + 1543 = 6473 and for second loop sum will be 12 14 + 16 + 18 = 60 (except 20 because loop is from 0 to 3 index) so result = 6473 + 60 = 6533.

Ques 4-How is search done in #include and #include “somelibrary.h” according to C standard?

a) When former is used, current directory is searched and when latter is used, standard directory is searched
b) When former is used, standard directory is searched and when latter is used, current directory is searched
c) When former is used, search is done in implementation defined manner and when latter is used, current directory is searched
d) For both, search for ‘somelibrary’ is done in implementation-defined places

Answer Explanation

ANSWER: For both, search for ‘somelibrary’ is done in implementation-defined places

Ques 5-What is the sequence for preprocessor to look for the file within <> ?

a) predefined location then the current directory
b) The current directory then the predefined location
c) The predefined location only
d) The current directory location

ANSWER:  (a) The predefined location then the current directory

Ques 6-Specify the 2 library functions to dynamically allocate memory?

a) malloc() and memalloc()
b) alloc() and memalloc()
c) malloc() and calloc()
d) memalloc() and faralloc()

ANSWER:(c) malloc() and calloc()

Ques 7- Output of the following program?

#include
int main()
{
int y=128;
const int x=y;
printf(“%d\n”, x);
return 0;
}

a. 128
b. Garbage value
c. Error
d. 0

ANSWER: (a) 128

Ques 8- What is the outpout of the following program?

#include

main()
{
enum { india, is=7, GREAT };

printf(“%d %d”, india, GREAT);
}
A – 0 1.

B – 0 2

C – 0 8

D – Compile error

Answer : C
Explanation
0 8, enums gives the sequence starting with 0. If assigned with a value the sequence continues from the assigned value

Ques 9- What is the output of the following program?

#include

int main () {

int var = 20; /* actual variable declaration */
int *ip; /* pointer variable declaration */

ip = &var; /* store address of var in pointer variable*/

printf(“Address of var variable: %x\n”, &var );

/* address stored in pointer variable */
printf(“Address stored in ip variable: %x\n”, ip );

/* access the value using the pointer */
printf(“Value of *ip variable: %d\n”, *ip );

return 0;
}

Output:

Address of var variable: bffd8b3c
Address stored in ip variable: bffd8b3c
Value of *ip variable: 20

Ques 10-What is the output of the following program?

#include
#include

double average(int num,…) {

va_list valist;
double sum = 0.0;
int i;

/* initialize valist for num number of arguments */
va_start(valist, num);

/* access all the arguments assigned to valist */
for (i = 0; i < num; i++) {
sum += va_arg(valist, int);
}

/* clean memory reserved for valist */
va_end(valist);

return sum/num;
}

int main() {
printf(“Average of 2, 3, 4, 5 = %f\n”, average(4, 2,3,4,5));
printf(“Average of 5, 10, 15 = %f\n”, average(3, 5,10,15));
}

Solution:

When the above code is compiled and executed, it produces the following result. It should be noted that the function average() has been called twice and each time the first argument represents the total number of variable arguments being passed. Only ellipses will be used to pass variable number of arguments.

Average of 2, 3, 4, 5 = 3.500000
Average of 5, 10, 15 = 10.000000

Ques 11- For 16-bit compilar range for integer constant is_____?

a)-3.4e38 to 3.4e38
b)-32767 to 32768
c)-32668 to 32667
d)-32768 to 32767

Answer & Solution

Answer: Option (d)

Solution: In a 16 Bit C compiler we have 2 bytes to store an integer, and 1 byte for a character.
For unsigned integers the range is 0 to 65535.
For signed integers the range is -32768 to 32767.
For unsigned character, 0 to 255

Time – 10 Mins

Questions – 2 Ques

Model Questions:-

Ques 1- Write a program in C to count the frequency of each element of an array.

solution:

#include

void main()
{
int arr1[100], fr1[100];
int n, i, j, ctr;

printf(“Count frequency of each element of an array:”);
printf(“————–“);

printf(“Input the number of elements to be stored in the array :”);
scanf(“%d”,&n);

printf(“Input %d elements in the array :\n”,n);
for(i=0;i<n;i++)
{
printf(“element – %d : “,i);
scanf(“%d”,&arr1[i]);
fr1[i] = -1;
}
for(i=0; i<n; i++)
{
ctr = 1;
for(j=i+1; j<n; j++)
{
if(arr1[i]==arr1[j])
{
ctr++;
fr1[j] = 0;
}
}

if(fr1[i]!=0)
{
fr1[i] = ctr;
}
}
printf(“The frequency of all elements of array :”);
for(i=0; i<n; i++)
{
if(fr1[i]!=0)
{
printf(“%d occurs %d times\n”, arr1[i], fr1[i]);
}
}
}

Sample Output:

Count frequency of each element of an array:

Input the number of elements to be stored in the array :3
Input 3 elements in the array :

element – 0 : 25
element – 1 : 12
element – 2 : 43

The frequency of all elements of array :
25 occurs 1 times
12 occurs 1 times
43 occurs 1 times

Ques 2-Write a program in C to insert New value in the array (unsorted list ).

solution:
#include

void main()
{
int arr1[100],i,n,p,x;

printf(“Insert New value in the unsorted array : “);
printf(“——————–“);
printf(“Input the size of array : “);
scanf(“%d”, &n);
/* Stored values into the array*/
printf(“Input %d elements in the array in ascending order:\n”,n);
for(i=0;i<n;i++)
{
printf(“element – %d : “,i);
scanf(“%d”,&arr1[i]);
}

printf(“Input the value to be inserted : “);
scanf(“%d”,&x);
printf(“Input the Position, where the value to be inserted :”);
scanf(“%d”,&p);

printf(“The current list of the array :\n”);
for(i=0;i<n;i++)
printf(“% 5d”,arr1[i]);
/* Move all data at right side of the array */
for(i=n;i>=p;i–)
arr1[i]= arr1[i-1];
/* insert value at given position */
arr1[p-1]=x;

printf(“After Insert the element the new list is :\n”);
for(i=0;i<=n;i++)
printf(“% 5d”,arr1[i]);
printf(“\n\n”);
}

Sample Output:

Insert New value in the unsorted array :
—————————————–
Input the size of array : 4
Input 4 elements in the array in ascending order:
element – 0 : 1
element – 1 : 8
element – 2 : 7
element – 3 : 10
Input the value to be inserted : 5
Input the Position, where the value to be inserted :2
The current list of the array :
1 8 7 10

After Insert the element the new list is :
1 5 8 7 10