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Find the 15th term of the series? 0,0,7,6,14,12,21,18

Question 0 Find the 15th term of the series? 0,0,7,6,14,12,21,18 Please add the answer in the comment section below.
#include <stdio.h>

int a1(int x);
int a2(int y);

void main()
{
int n;
scanf("%d",&n);
if(n%2==0)
a1(n/2);
else
a2(n/2+1);
}

int a1(int x)
{
int s=0;
for(int i=0;i<x-1;i++)
{
s=s+6;
}
printf("%d",s);
}

int a2(int x)
{
int s=0;
for(int i=0;i<x-1;i++)
{
s=s+7;
}
printf("%d",s);
}
//C++ Program
#include <iostream>
using namespace std;
int main()
{
//we would be init. the variables here
int val, extra;
cout<<"Enter the term you want to print: ";
//user input
cin>>val;
//logic for merging to different patterns
if(val==0||val==1)
{
cout<<0;
return 0;
}
else if(val%2==0)
{
val=val/2;
extra=6;
}
else
{
val=val/2+1;
extra=7;
}
//the code brain ends here
//now, we will print o/p
cout<<(val-1)*extra;
return 0;
}
import java.util.Scanner;

public class Series{

public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
int n;
n=sc.nextInt();
int arr[]=new int[n];
int i,k=0;
int a=0,b=0;
arr[0]=a;
k++;
arr[1]=b;
k++;
for(i=1;i<=n-2;i++)
{

if(i%2!=0)
{

a=a+7;
arr[k]=a;

k++;
}
else
{

b=b+6;
arr[k]=b;

k++;
}
}
System.out.print(arr[n-1]);

}
}
val = int(input('enter the number: '))

x=0

y=0

for i in range(1,val+1):

if(i%2!=0):

x= x+7

else:

y = y+6

if(val%2!=0):

print(' {} term in accordance to the program is {}'.format(val,x-7))

else:

print('{} term in accordance to the program is {}'.format(val,y-6))

6 comments on “Find the 15th term of the series? 0,0,7,6,14,12,21,18”


  • Priti kumari

    public class Fifteen
    {

    public static void main(String[] args)
    {

    int a[]=new int[20];
    int k=0;
    for(int i=0;i<9;i++)
    {
    for(int j=0;j<2;j++)
    {
    if(i+1%2==0)
    {
    a[k]=i*7;
    k++;
    }
    else
    a[k]=i*6;
    k++;
    }
    }
    System.out.println(a[14]);
    }

    }


  • Shardul Negi

    //Find the 15th term of the series?
    //0,0,7,6,14,12,21,18, 28
    #include
    void main()
    {

    int i=0,j=0,k=0,l=0,m=0,lt;
    for(i=0,j=1;i<15;i+=2,j+=2){

    k=7*m;
    l=6*m;
    //printf("%d %d ",k,l);
    m++;
    lt=l;
    }
    printf("%d",lt);
    }


  • siva ganesh

    #include
    int main()
    {
    int n,t,d,a;
    scanf(“%d”,&n);
    if(n%2==1)
    {
    a=0;
    d=(n/2)+1;
    t=a+(d-1)*7;
    printf(“%d”,t);
    }
    else
    {
    a=0;
    d=(n/2);
    t=a+(d-1)*6;
    printf(“%d”,t);
    }
    return 0;
    }


  • Raushan Jha

    import java.util.*;
    class SeriesAP2
    {
    public static void main(String args[])
    {
    Scanner s=new Scanner(System.in);
    int n=s.nextInt();
    if(n==1 || n==2)
    {
    System.out.println(“0″);
    }
    if(n>=3)
    {
    if(n%2!=0)
    {
    n=n/2;
    int tn1=7+(n-1)*7;
    System.out.println(tn1+” “);
    }
    else
    {
    n=n/2-1;
    int t2=6+(n-1)*6;
    System.out.println(t2+” “);
    }
    }
    }
    }


  • soumen pramanik

    #include
    int a1(int x);
    int a2(int y);
    void main()
    {
    int n;
    scanf(“%d”,&n);
    if(n%2==0)
    a1(n/2);
    else
    a2(n/2+1);
    }
    int a1(int x)
    {
    int s=0;
    for(int i=0;i<x-1;i++)
    {
    s=s+6;
    }
    printf("%d",s);
    }
    int a2(int x)
    {
    int s=0;
    for(int i=0;i<x-1;i++)
    {
    s=s+7;
    }
    printf("%d",s);
    }