eLitmus Cryptarithmetic Problem – 1

J  E
B  B
----
J  E
J  E  A
--------
B  A  D  E

Assume that E = 4

Cryptarithmetic Questions asked in eLitmus 1

The Cryparithmetic methods discussed below are developed by PrepInsta only and available on 2 PrepInsta owned websites only. Anyone copying the method will be legally sued as these are not open source but are PrepInsta’s Proprietary methods

 1. Value of 5B? (a) 15 (b) 10 (c) 5
 2. Value of B + A? (a) 7 (b) 5 (c) 1 (d) 8
 3. Value of  D ? (a) 4 (b) 3 (c) 7 (d) Can not be determined
It is highly suggested to go through these before solving
- Cryptarithmetic Introduction
- How to Solve Cryptarithmetic Problems
Row 1         J  E
Row 2         B  B
Row 3         ----
Row 4         J  E
Row 5      J  E  A
Row 6     --------
Row 7   B  A  D  E

Assume that E = 4

Step 1

• Clearly, from the Row 2 row where
• B is written in common multiplication
• J E is multiplied with B and results in B, which results in J E.
• Thus, the B value is 1

Step 2

• In Row 4 : E + A = E.
• This, only possible when A value is 0
Row 1         J  E
Row 2         1  1
Row 3         ----
Row 4         J  E
Row 5      J  E  0
Row 6     --------
Row 7   1  0  D  E

Step 3

• Now in Row 5 and Row 7
• J + nothing(Row 4) gives us 10.
• Thus, there must be 1 carry from the previous step and J value must be 9
• Now, the problem looks like-
Row 1            9  E
Row 2            1  1
Row 3            ----
Row 4  (carry)1  9  E
Row 5         9  E  0
Row 6         --------
Row 7      1  0  D  E

Step 4

• 9 + E = D
• Now, from the previous step, there can not be any carry
• As E + 0 = E, and E can have values between E = {0,9}
• Max value of E can be 8 as J = 9 (already taken)
• Thus, step 9 + E = D will have no carry from the previous step
• However, this is generating carry to the next step
• Thus, 9 + E = D + 10
• E – D = 1
• Since, E = 4 => D = 3

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• Atulya PrepInsta

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