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When at least 2 women are included.
The committee may consist of 3 women, 2 men :
It can be done in 4C3*6C2 ways
or, 4 women, 1 man : It can be done in 4C4*6C1ways
or, 2 women, 3 men : It can be done in 4C2*6C3 ways.
Total number of ways of forming the committees
= 4C2*6C3+4C3*6C2+4C4*6C1
= 6 x 20 + 4 x 15 + 1x 6
= 120 + 60 + 6 =186
good questions!!nice
please provide the solution to the above questions.