Cryptarithmetic Problem – Possible ways of getting 3, 4, 5

March 20, 2020

Possible ways of getting 3

Unit Digit = 3 e.g. 3, 63 A x B = _0	Explanation
1 x 3 = _3(03) or 3 x 1 = _3(03)	1 x 3 = _3(03) A x B =_3 A = 1 B = 3 3 x 1 = _3(03) A x B =_3 A = 3 B = 1
9 x 7 = _3(63) or 7 x 9 = _3(63)	9 x 7 = _3(63) A x B =_3 A = 9 B = 7 7 x 9 = _3(63) A x B =_3 A = 7 B = 9

Possible ways of getting 4

Unit Digit = 4 e.g. 4, 14, 24, 54, 64 A x B = _4	Explanation
1 x 4 =_4(04) or 4 x 1 =_4(04)	1 x 4 =_4(04) A x B =_4 A = 1 B = 4 4 x 1 =_4(04) A x B =_4 A = 4 B = 1
2 x 2 =_4(04)	2 x 2 =_4(04) A x B =_4 A = 2 B = 2
7 x 2 =_4(14) or 7 x 7 =_4(14)	7 x 2 =_4(14) A x B =_4 A = 7 B = 2 2 x 7 =_4(14) A x B =_4 A = 2 B = 7
8 x 3 =_4(24) or 3 x 8 =_4(24)	8 x 3 =_4(24) A x B =_4 A = 8 B = 3 3 x 8 =_4(24) A x B =_4 A = 3 B = 8
6 x 4 =_4(24) or 4 x 6 =_4(24)	6 x 4 =_4(24) A x B =_4 A = 6 B = 4 4 x 6 =_4(24) A x B =_4 A = 4 B = 6
9 x 6 =_4(54) or 6 x 9 =_4(54)	9 x 6 =_4(54) A x B =_4 A = 9 B = 6 2 x 5 =_4(54) A x B =_4 A = 6 B = 9
8 x 8 =_4(64)	8 x 8 =_4(64) A x B =_4 A = 8 B = 8

Possible ways of getting 5

Unit Digit = 5 e.g. 5, 15, 25, 35, 45 A x B = _5	Explanation
1 x 5 =_5(05) or 5 x 1 =_5(05)	1 x 5 =_5(05) A = 1 B = 5 5 x 1 =_5(05) A = 5 B = 1
3 x 5 =_5(15) or 5 x 3 =_5(15)	3 x 5 =_5(15) A = 3 B = 5 5 x 3 =_5(15) A = 5 B = 3
5 x 5 =_5(25)	5 x 5 =_5(25) A = 5 B = 5
7 x 5 =_5(35) or 5 x 7 =_5(35)	7 x 5 =_5(35) A = 7 B = 5 5 x 7 =_5(35) A = 5 B = 7
9 x 5 =_5(45) or 5 x 9 =_5(45)	9 x 5 =_5(45) A = 9 B = 5 5 x 9 =_5(45) A = 5 B = 9

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