# Cryptarithmetic Problem – Possible ways of getting 3, 4, 5

## Possible ways of getting 3

Unit Digit = 3 e.g. 3, 63

A x B = _0
Explanation
1 x 3 = _3(03)
or
3 x 1 = _3(03)
1 x 3 = _3(03)
A x B =_3 A = 1 B = 3
3 x 1 = _3(03)
A x B =_3 A = 3 B = 1
9 x 7 = _3(63)
or
7 x 9 = _3(63)
9 x 7 = _3(63)
A x B =_3 A = 9 B = 7
7 x 9 = _3(63)
A x B =_3 A = 7 B = 9

## Possible ways of getting 4

Unit Digit = 4 e.g. 4, 14, 24, 54, 64

A x B = _4
Explanation
1 x 4 =_4(04)
or
4 x 1 =_4(04)
1 x 4 =_4(04) A x B =_4 A = 1 B = 4
4 x 1 =_4(04) A x B =_4 A = 4 B = 1
2 x 2 =_4(04)2 x 2 =_4(04) A x B =_4 A = 2 B = 2
7 x 2 =_4(14)
or
7 x 7 =_4(14)
7 x 2 =_4(14) A x B =_4 A = 7 B = 2
2 x 7 =_4(14) A x B =_4 A = 2 B = 7
8 x 3 =_4(24)
or
3 x 8 =_4(24)
8 x 3 =_4(24) A x B =_4 A = 8 B = 3
3 x 8 =_4(24) A x B =_4 A = 3 B = 8
6 x 4 =_4(24)
or
4 x 6 =_4(24)
6 x 4 =_4(24) A x B =_4 A = 6 B = 4
4 x 6 =_4(24) A x B =_4 A = 4 B = 6
9 x 6 =_4(54)
or
6 x 9 =_4(54)
9 x 6 =_4(54) A x B =_4 A = 9 B = 6
2 x 5 =_4(54) A x B =_4 A = 6 B = 9
8 x 8 =_4(64)8 x 8 =_4(64) A x B =_4 A = 8 B = 8

## Possible ways of getting 5

Unit Digit = 5 e.g. 5, 15, 25, 35, 45

A x B = _5
Explanation
1 x 5 =_5(05)
or
5 x 1 =_5(05)
1 x 5 =_5(05) A = 1 B = 5
5 x 1 =_5(05) A = 5 B = 1
3 x 5 =_5(15)
or
5 x 3 =_5(15)
3 x 5 =_5(15) A = 3 B = 5
5 x 3 =_5(15) A = 5 B = 3
5 x 5 =_5(25)5 x 5 =_5(25) A = 5 B = 5
7 x 5 =_5(35)
or
5 x 7 =_5(35)
7 x 5 =_5(35) A = 7 B = 5
5 x 7 =_5(35) A = 5 B = 7
9 x 5 =_5(45)
or
5 x 9 =_5(45)
9 x 5 =_5(45) A = 9 B = 5
5 x 9 =_5(45) A = 5 B = 9