# Telling the Number of days in a given month of a given year.

In this page we’ll take a look at a program using which we can determine the number of days in a given month of a given year. We’ll use simple If-Else Statements for our desired results with a corresponding print Statement in each block. Also, we’ll have to check for a the entered year to be a leap year since in that case February will have 29 days.

## Algorithm

• Take the input from the user in the form of the month and the year of which he wants to know the number of days.
• Use Conditional Statements (If-Else) to determine the number of days.
• Since a leap year is completely divisible by 4, So, For a leap year use a conditional statement in which we check for the month February as well as a leap year.
• Write print statements in the respective conditional blocks.

## C Program

```#include <stdio.h>
int main()
{
int m;
int y;
printf("Please enter a number corresponding to a month.\n1 - January\n2 - February\n3 - March\n4 - April\n5 - May\n6 - June\n7 - July\n8 - August\n9 - September\n10 - October\n11 - November\n12 - December\n");
scanf("%d",&m);
scanf("%d",&y);
if(m==1 ||m==3 ||m==5 ||m==7 ||m==8 ||m==10 ||m==12)
printf("No. of days in this month is 31");//for months with 31 days
else if(m==2 && y%4==0)
printf("No. of days in this month is 29");//for a february in a leap year
else if(m==2 && y%4!=0)
printf("No. of days in this month is 28");//for a february in a normal year
else
printf("No. of days in this month is 30");//for a month with 30 days
return 0;
}```

```Please enter a number corresponding to a month.
1 - January
2 - February
3 - March
4 - April
5 - May
6 - June
7 - July
8 - August
9 - September
10 - October
11 - November
12 - December
2