C Arrays Questions 3

June 23, 2019

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Question 1

Time: 00:00:00
For the following declaration

int *p[10], arr[10][10];

Which of these statements will not give run time error?

I A[2] II A[2][3] III B[1] IV B[2][3]

Only II and IV

Only II and IV

Only II III and IV

Only II III and IV

Only IV

Only IV

Only I II and IV

Only I II and IV

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Question 2

Time: 00:00:00
What will be printed by the following C code?

#include<stdio.h> int main() { int i; int a[5] = {0}; for (i = 0; i <= 5; i++) printf("%d ", a[i]); return 0; }

(null)

(null)

Program crashes and shows compilation error.

Program crashes and shows compilation error.

0 0 0 0 0 and some garbage value.

0 0 0 0 0 and some garbage value.

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Question 3

Time: 00:00:00
Which is the following printf command if addted to the code following will print 17 ?

#include<stdio.h> int main() { int arr[20][25][30] = {0}; arr[4][8][7] = 17; return 0; }

printf("%d",***( ( (arr+4)+8)+7) );

printf("%d",***( ( (arr+4)+8)+7) );

printf("%d",*( ( (arr+4)+8)+7) );

printf("%d",*( ( (arr+4)+8)+7) );

printf("%d",*( *( *(arr+4)+8)+7) );

printf("%d",*( *( *(arr+4)+8)+7) );

printf("%d",( ( (arr+4)+8)+7) );

printf("%d",( ( (arr+4)+8)+7) );

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Question 4

Time: 00:00:00
What will be the output of the following C code ?
#include <stdio.h>

int main()

{

    char p;

    char arr[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

    p = (arr + 1)[7];

    printf("%d", p);

    return 0;

}

Compilation error.

Compilation error.

8

8

9

9

7

7

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Question 5

Time: 00:00:00
What is meaning of the following declaration ?

int (*p)[10];

p is a pointer to 10 integers.

p is a pointer to 10 integers.

p is a pointer to an array with 10 integer.

p is a pointer to an array with 10 integer.

Compile error. int *p[10] is valid.

Compile error. int *p[10] is valid.

p is an array of 10 pointers to integers.

p is an array of 10 pointers to integers.

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