Calculator Using Switch Case

August 13, 2024

Calculator by Switch Case

We will write a C program to make a basic calculator by using switch cases for understanding the basic structure of programming. In this program , we can calculate numbers easily by using proper syntax and algorithms.

Calculator Using Switch Case

Working of Program :

In the program, we will require two or more numbers from the user to perform some basic operations for calculation.

Problem 1

Write a program to make a calculator to perform some basic operations using switch case.

  • If the operator is ‘+’, then print the addition operation on the given integer.
  • If the operator is ‘-’, then print the subtraction operation on the given integer.
  • If the operator is ‘*’, then print the multiplication operation on the given integer.
  • If the operator is ‘/’, then print the division operation on the given integer.

Code

Run 
#include<stdio.h>
int main ()
{
  int num1, num2;
  float result;
  char ch;
  printf ("Enter first number = ");
  scanf ("%d", &num1);
  printf ("Enter second number = ");
  scanf ("%d", &num2);
  printf ("Choose operator to perform operations = ");
  scanf (" %c", &ch);
  result = 0;
  switch (ch)
    {
    case '+':
      result = num1 + num2;
      break;
    case '-':
      result = num1 - num2;
      break;
    case '*':
      result = num1 * num2;
      break;
    case '/':
      result = num1 / num2;
      break;
    default:
      printf ("Invalid operation\n");
    }
  printf ("Result: %d %c %d = %f\n", num1, ch, num2, result);
  return 0;
}

Output

Enter first number = 6
Enter second number = 7
Choose operator to perform operations = +
Result: 6 + 7 = 13.000000

Conditional Statement in C

Loops in C

Arrays in C

Function in C

Boolean in C

 

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