This series is a mixture of 2 series – all the odd terms in this series form a geometric series and all the even terms form yet another geometric series. 

June 23, 2019

Consider the following series: 1,1,2,3,4,9,8,27,16,81,32,243,64,729,128,2187…

This series is a mixture of 2 series – all the odd terms in this series form a geometric series and all the even terms form yet another geometric series. Write a program to find the Nth term in the series.

The value N in a positive integer that should be read from STDIN. The Nth term that is calculated by the program should be written to STDOUT. Other than value of n th term,no other character / string or message should be written to STDOUT. For example , if N=16, the 16th term in the series is 2187, so only value 2187 should be printed to STDOUT.

You can assume that N will not exceed 30.

Please comment the code in other languages below – 

#include <stdio.h>
#include<math.h>

int main() {
//code
int n;
scanf(“%d”, &n);
if(n % 2 == 1)
{
int a = 1;
int r = 2;
int term_in_series = (n+1)/2;
int res = pow(2, term_in_series – 1);
printf(“%d “, res);
}
else
{
int a = 1;
int r = 3;
int term_in_series = n/2;
int res = pow(3, term_in_series – 1);
printf(“%d “, res);
}

return 0;
}

Please send code in other langauges

16 comments on “This series is a mixture of 2 series – all the odd terms in this series form a geometric series and all the even terms form yet another geometric series. ”


  • D.YAMINI

    n=int(input())
    l=[]
    m=0
    #print(3^8)
    if n>30:
    print(“n should not exceed 30”)
    elif n==1 or n==2:
    print(“1”)
    elif n>2 and n%2==0:
    m= int(n/2) -1
    print(pow(3,m))
    elif n>1 and n%2!=0:
    m= int(n/2)
    print(pow(2,m))
    else: print(“invalid input”)

    0

  • goutham

    #python
    n=int(input(“enter the number: “))
    a=1
    b=1
    for i in range(2,n):
    if i%2!=0:
    a=a*3
    if i%2==0:
    b=b*2
    if n%2==0:
    print(“The {} term in the series is {}”.format(n,a))
    else:
    print(“The {} term in the series is {}”.format(n,b))

    0

    • Anil

      n=int(input())
      y=2*n+1
      x=[0]*y
      for i in range(0,2*n,2):
      x[i]=i
      for i in range(0,2*n//2):
      x[2*i+1]=i
      for i in range(2*n):
      print(x[i])

      0
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