Command Line Program to Reverse a Number

C/c++

#include <stdio.h>
int main()
{
    int n, reversedNumber = 0, remainder;

    printf("Enter an integer: ");
    scanf("%d", &n);

    while(n != 0)
    {
        remainder = n%10;
        reversedNumber = reversedNumber*10 + remainder;
        n /= 10;
    }

    printf("Reversed Number = %d", reversedNumber);

    return 0;
}

Java

public class ReverseNumber {

    public static void main(String[] args) {

        int num = 1234, reversed = 0;

        while(num != 0) {
            int digit = num % 10;
            reversed = reversed * 10 + digit;
            num /= 10;
        }

        System.out.println("Reversed Number: " + reversed);
    }
}

Command Line Programming

Please comment your own version of code in the comment section below –

 
#include
#include
int main(int argc, char *argv[])
{
if(argc==1)
{
printf("No Arguments");
return 0;
}
else
{
int n,reverseNumber,temp,rem;
n=atoi(argv[1]);
temp=n;
reverseNumber=0;
while(temp)
{
rem=temp%10;
reverseNumber=reverseNumber*10+rem;
temp=temp/10;
}
printf("%d",reverseNumber);
return 0;
}
}