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Print Diamond Number Pattern Program Type 1
Pattern22
PRINTING PATTERN:
3
44
555
6666
555
44
3
PREREQUISITE:
Basic knowledge of C language and use of loops.
ALGORITHM:
- Take the number of rows as input from the user and store it in any variable.(‘r‘ in this case).
- Run a loop ‘r’ number of times to iterate through each of the rows. From i=0 to i<r. The loop should be structured as for( i=0 ; i
- Use an if condition to to print the top half of the pyramid. if (i<=r/2). Then run a loop from j=0 to j<=i. The loop should be structured as for(j=0 ; j<=i ; j++)
- Inside this loop print i+3.
- Else run a different loop from j=i to jThe loop should be structured as for( j=i ; j
- Inside this loop print (r-i+2).
- Inside the main loop print a newline to move to the next line after each row is printed.
Input:
3 4
Output:
3
44
555
6666
555
44
3
Input :
4 4
Output:
4
55
666
7777
666
55
4
Code 1
import java.util.*;
class Main
{
public static void main(String[] args)
{
Scanner sc=new Scanner(System.in);
int i,j,count=0;
int s=sc.nextInt();
int N=sc.nextInt();
for(i=s;count<4;count++)
{
for(j=0;j<count+1;j++)
System.out.print(i);
System.out.println();
i=i+1;
}
for(i=s+N-2;count>0;count--)
{
for(j=0;j<count-1;j++)
System.out.print(i);
System.out.println();
i=i-1;
}
}
}
import java.util.*;
public class Main
{
public static void main(String[] args) {
int i,j,n;
Scanner in= new Scanner(System.in);
System.out.println(“enter no of rows: “);
n= in.nextInt();
int num=3;
for(i=1;i<=n;i++)
{
for(j=1;j=1;i–)
{
for(j=1;j<=i;j++)
{
System.out.print(num-2);
}
num–;
System.out.println();
}
}
}
Very usefull pattern programmes for claring the amcat test